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3 years ago

Please help me please I need help!!!!!!!!!!!!!!!!!!!hshdjdndndbdbnfjfkfkfkdkdkfkfjdjfiid

Mathematics

1 answer:

Serggg [28]3 years ago

6 0

y = (x - 2)(x + 5) First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

y = x² + 3x - 10

Next I would plug in a number for x to find its y value. I will plug in 0

y = 0² + 3(0) - 10

y = -10

(0, -10) [this is the y-intercept (the y value when x = 0)]

Your answer is Graph A because the y-intercept is (0,-10)

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8 0

3 years ago

Read 2 more answers

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julsineya [31]

Answer:

The first and third is correct.

Step-by-step explanation:

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3 years ago

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JulijaS [17]

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3 years ago

The midpoint of AB is M(1, -4). If the coordinates of A are (-3,-6), what are the coordinates of B?

kramer

Answer:

The coordinates of B is (5,-2)

Step-by-step explanation:

In order to find the coordinates of B, you have to use midpoint formula. Then substitute the following values into the formula :

$m = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} )$

Let (x1,y1) be A (-3,-6),

Let (x2,y2) be B,

Let midpoint be M (1,-4),

$(1, - 4) = (\frac{ - 3 + x2}{2} , \frac{ - 6 + y2}{2} )$

$by \: comparison, \:$

$\frac{ - 3 + x2}{2} = 1$

$- 3 + x2 = 2$

$x2 = 5$

$\frac{ - 6 + y2}{2} = - 4$

$- 6 + y2 = - 8$

$y2 = - 2$

6 0

3 years ago

Rewrite in simplest radical form 1 over x^(−3/6). Show each step of your process.

meriva

$\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}}$

$\bf \rule{34em}{0.25pt}\\\\ \cfrac{1}{x^{-\frac{3}{6}}}\implies x^{\frac{3}{6}}\implies x^{\frac{1}{2}}\implies \sqrt[2]{x^1}\implies \sqrt{x}$

5 0

3 years ago