For waht value of the variable is 'x' 3 times less than the 45-10x

1 answer:

4 0

We have to find for what value of variable is x 3 times less than the 45 - 10 x :
x = ( 45 - 10 x ) / 3
3 x = 45 - 10 x
3 x + 10 x = 45 - 10 x + 10 x
13 x = 45
x = 45 : 13
Answer:
x = 45/13

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10 ft

Gnom [1K]

Answer:

105.12 feets

Step-by-step explanation:

From the figure x we can identify a rectangle and a semicircle :

Area of rectangle = Length * width

Area = 8 * 10 = 80 feet²

The Area of a semicircle = 1/2πr²

Radius, r = 8 /2 = 4 feets

A = 1/2 * 3.14 * 4²

A = 3.14 * 8

A = 25.12 feet²

Area of figure = 80 + 25.12 = 105.12 feets

4 0

3 years ago

If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]? a)29.5 b)30 c)43 d)120

avanturin [10]

$\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
f(x)= x^3-x \qquad 
\begin{cases}
x_1=1\\
x_2=5
\end{cases}\implies \cfrac{f(5)-f(1)}{5-1}
\\\\\\
\cfrac{[5^3-5]~-~[1^3-1]}{4}\implies \cfrac{125-5~~-~~0}{4}\implies \cfrac{120}{4}\implies 30$