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Stolb23 [73]
3 years ago
8

At 2:00 p.m. two cars start toward each other from towns 240 miles apart. If the rate of one car is 10 mph faster than the other

, how fast does each car go if they meet at 5:00 p.m.? If 3x represents the distance that the slower car traveled, then which expression represents the distance the faster car traveled?
Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
5 0
Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
mestny [16]3 years ago
4 0

Answer: 3x45=135

Step-by-step explanation:Let’s call the speed of the slower car S, then the speed of the other is S+10mph.

At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).

But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles

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Step-by-step explanation:

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So we'll start with y= - ax - 1 We'll also make the assumption that a = 1

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