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poizon [28]
3 years ago
13

How do I convert a mixed-number percentage to simplified?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
6 0

Answer:


1/3



Step-by-step explanation:


So, for this you need to know two general things. How to convert from a mixed number to a decimal form (or improper fraction and then turn that into a decimal), and then to convert between fractions, decimals and percents. In math it becomes standard practice to use improper fractions rather than mixed numbers , just as a heads up.


Now first, to explain and in your problem, we want to convert a mixed number into a decimal form. With a mixed number you can think of it like addition. In your case it's 33 + 1/3. So our decimal form is going to be thirty three point something. If the fraction part was more than 1 (the numerator being greater than the denominator, so an improper fraction) it would actually change the non fraction number. So if it was 33 4/3 it would turn into 34 point something.


1/3 is simply .3 repeating, so this turns into 33.3% repeating. Now to get from a percent to whole decimal you just divide it by 100, or more simply move the decimal place to the left twice. This leaves us with .333 repeating or .3 repeating, since we are just adding two more 3s to it. Now, what does this mean? It's just 1/3.


Let me know if you would like a quick explanation for general rules in going between decimals, percents and fractions, because I could write that up pretty quick, and let me know if you didn't understand this explanation.

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Answer:

Eating dinner and eating dessert are dependent events because

P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

P(dinner and desert) = 0.5 ⇒ answer A

Step-by-step explanation:

* Lets study the meaning independent and dependent probability  

- Two events are independent if the result of the second event is not

  affected by the result of the first event

- If A and B are independent events, the probability of both events  

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- P (A and B) = P(A) · P(B)

* Lets solve the question  

∵ There is a 90% chance that a person eats dinner

∴ P(eating dinner) = 90/100 = 0.9

∵ There is a 60% chance a person eats dessert

∴ P(eating dessert) = 60/100 = 0.6

- If eating dinner and dating dessert are independent events, then

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∵ P(eating dinner and dessert) = P(eating dinner) . P(eating dessert)

∴ P(eating dinner and dessert) = 0.9 × 0.6 = 0.54

∵ There is a 50% chance the person will eat dinner and dessert

∴ P(eating dinner and dessert) = 50/100 = 0.5

∵ P(eating dinner and dessert) ≠ P(eating dinner) . P(eating dessert)

∴ Eating dinner and eating dessert are dependent events because

  P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

  P(dinner and desert) = 0.5

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If the original square had a side length of
irina [24]

Answer:

Part a) The new rectangle labeled in the attached figure N 2

Part b) The diagram of the new rectangle with their areas  in the attached figure N 3, and the trinomial is x^{2} +11x+28

Part c) The area of the second rectangle is 54 in^2

Part d) see the explanation

Step-by-step explanation:

The complete question in the attached figure N 1

Part a) If the original square is shown below with side lengths marked with x, label the second diagram to represent the new rectangle constructed by increasing the sides as described above

we know that

The dimensions of the new rectangle will be

Length=(x+4)\ in

width=(x+7)\ in

The diagram of the new rectangle in the attached figure N 2

Part b) Label each portion of the second diagram with their areas in terms of x (when applicable) State the product of (x+4) and (x+7) as a trinomial

The diagram of the new rectangle with their areas  in the attached figure N 3

we have that

To find out the area of each portion, multiply its length by its width

A1=(x)(x)=x^{2}\ in^2

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The total area of the second rectangle is the sum of the four areas

A=A1+A2+A3+A4

State the product of (x+4) and (x+7) as a trinomial

(x+4)(x+7)=x^{2}+7x+4x+28=x^{2} +11x+28

Part c) If the original square had a side length of  x = 2 inches, then what is the area of the  second rectangle?

we know that

The area of the second rectangle is equal to

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substitute the value of x in the area of each portion

A1=(2)(2)=4\ in^2

A2=(4)(2)=8\ in^2

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A4=(4)(7)=28\ in^2

A=4+8+14+28

A=54\ in^2

Part d) Verify that the trinomial you found in Part b) has the same value as Part c) for x=2 in

We have that

The trinomial is

A(x)=x^{2} +11x+28

For x=2 in

substitute and solve for A(x)

A(2)=2^{2} +11(2)+28

A(2)=4 +22+28

A(2)=54\ in^2 ----> verified

therefore

The trinomial represent the total area of the second rectangle

7 0
3 years ago
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