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WINSTONCH [101]
2 years ago
14

A box is in the shape of an equilateral triangular prism. if the box is to be covered with paper on its lateral sides, how many

square inches of paper are needed?
Mathematics
1 answer:
Zarrin [17]2 years ago
7 0

The total surface area of the triangular prism that has a height of h and the side length of a is given below.

\rm a(\dfrac{\sqrt3}{2} \ a + 3h)

<h3>What is a triangular prism?</h3>

A triangular prism is a closed solid that has two parallel triangular bases connected by a rectangle surface.

A box is in the shape of an equilateral triangular prism.

If the box is to be covered with paper on its lateral sides.

Let a be the side length of the equilateral triangle and h be the height of the prism.

Then the surface area of the triangular prism will be

Surface area = 2 × area of triangle + 3 × area of the rectangle

The area of the triangle will be

\rm Area\ of\ triangle = \dfrac{\sqrt{3}a^2}{4}

The area of the rectangle will be

\rm Area \ of \ rectangle = a \ h

Then the total surface area will be

\rm Surface\ area =  2 \times \dfrac{\sqrt3 a^2 }{4} + 3 ah\\\\\\Surface\ area =  a(\dfrac{\sqrt3}{2} \ a + 3h)

More about the triangular prism link is given below.

brainly.com/question/21308574

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Full question and options​
LekaFEV [45]

Answer:

D

Step-by-step explanation:

A triangle is always determined by the names of its angles. If, for any reason, you wanted to label it by its side names(which I don't even think you can do but assuming you wanted to), you dont even have the names for all three sides here. So, it can only be d. A, X, and T are the three angle names for this triangle, so this is triangle ATX or AXT.

8 0
2 years ago
Read 2 more answers
Domain:<br> I need the domain
masha68 [24]

Answer:

Domain:The set of possible input values (using the “x” variable), which produce an output from a function.

Step-by-step explanation:

have a great day :)

6 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.
Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Step-by-step explanation:

GIven that:

f(x) = 5e^{-x^2} cos (4x)

The Maclaurin series of cos x can be expressed as :

\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+...  \ \ \ (1)}

\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0}  \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!}  -\dfrac{x^6}{3!}+... \ \ \  (2)}

From equation(1), substituting x with (4x), Then:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}

The first three terms of cos (4x) is:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}

\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}

\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}

Multiplying equation (2) with (3); we have :

\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }

\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Finally , multiplying 5 with \mathtt{ e^{-x^2} cos (4x) } ; we have:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

7 0
3 years ago
Guys pls help me!!!!!!
kumpel [21]

Answer:

x=32

Step-by-step explanation:

7 0
2 years ago
Find the principal amount invested if there is $9300 in the account after 5 years and earned 4% simple interest per year.
Zielflug [23.3K]

Answer:

11314.87379 (This is still rounded).

Step-by-step explanation:

Year 1:

9300*4%=372. 9300+372=9672.

Year 2:

9672*4%=386.88. 386.88=10058.88.

Year 3:

10058.88*4%=402.3552. 402.3552+10058.88=10461.2352.

Year 4:

10461.2352*4%=418.449408. 418.449408+10461.2352=10879.68461

Year 5:

10879.68461*4%=435.1873843. 435.1873843+10879.68461=11314.87379.

4 0
2 years ago
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