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Ivan
2 years ago
5

A triangle has a base of 9 feet and a height of 12 ft. What is the area of a triangle? A. 42ft^2 B. 54 ft^2 C. 84 ft^2 D. 108 ft

^2​

Mathematics
2 answers:
Llana [10]2 years ago
8 0

Answer:

The correct answer is option B. 54 ft^2

Step-by-step explanation:

Formula:-

Area of triangle

Area A = bh/2

b - Base of triangle

h - Height of triangle

To find the area of triangle

Here base b = 9 ft and height h = 12 ft

Area, A = bh/2 = (9 * 12)/2 = 54 ft^2

Therefore the area of given triangle is 54 ft^2

The correct answer is option B. 54 ft^2

elena55 [62]2 years ago
5 0

Answer:54sqft

Step-by-step explanation:

A=b*h/2

A=9*12/2=54sqft

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Which statement describes the inverse of m(x) = x2 – 17x?
stealth61 [152]

Answer:

The correct option is;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

Step-by-step explanation:

The given information is that m(x) = x² - 17·x

The above equation can be written in the form;

y = x² - 17·x

Therefore;

0 = x² - 17·x - y

From the general solution of a quadratic equation, 0 = a·x² + b·x + c we have;

x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}

By comparison to the equation,0 = x² - 17·x - y, we have;

a = 1, b = -17, and c = -y

Substituting the values of a, b and c into the formula for the general solution of a quadratic equation, we have;

x = \dfrac{-(-17)\pm \sqrt{(-17)^{2}-4\times (1) \times (-y)}}{2\times (1)} = \dfrac{17\pm \sqrt{289+4\cdot y}}{2}

Which can be simplified as follows;

x =  \dfrac{17\pm \sqrt{289+4\cdot y}}{2}= \dfrac{17}{2} \pm \dfrac{1}{2}  \times \sqrt{289+4\cdot y}} = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +\dfrac{4\cdot y}{4} }}

And further simplified as follows;

x = \dfrac{17}{2} \pm \sqrt{\dfrac{289}{4} +y }} = \dfrac{17}{2} \pm \sqrt{y + \dfrac{289}{4} }}

Interchanging x and y in the function of the inverse, m⁻¹(x), we have;

m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }}

We note that the maximum or minimum point of the function, m(x) = x² - 17·x found by differentiating the function and equating the result to zero, gives;

m'(x) = 2·x - 17 = 0

x = 17/2

Similarly, the second derivative is taken to determine if the given point is a maximum or minimum point as follows;

m''(x) = 2 > 0, therefore, the point is a minimum point on the graph

Therefore, as x increases past the minimum point of 17/2, m⁻¹(x) increases to give;

The \ domain \ restriction \ x \geq \dfrac{17}{2} \ results \ in \ m^{-1}(x) = \dfrac{17}{2} \pm \sqrt{x + \dfrac{289}{4} }} to increase m⁻¹(x) above the minimum.

8 0
2 years ago
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creativ13 [48]

Answer:

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Step-by-step explanation:

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Givens

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r = d/t

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The easiest way to do this is to change the fractions to decimals.

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r = 7 miles per hour.

7 0
2 years ago
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Answer:

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Step-by-step explanation:

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6 0
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Nikolay [14]
Autum needs 9 rings per day
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Alina [70]

Answer:

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7 0
2 years ago
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