Answer:
Analyzed and Sketched.
Step-by-step explanation:
We are given 
To sketch the graph we need to find 2 components.
1) First derivative of y with respect to x to determine the interval where function increases and decreases.
2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.
is absolute maximum
is the point concavity changes from down to up.
Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.
The graph is given in the attachment.
Let's simplify step-by-step.<span><span><span><span>8.9x</span>−5</span>−<span>6.8x</span></span>+8</span><span>=<span><span><span><span><span><span>8.9x</span>+</span>−5</span>+</span>−<span>6.8x</span></span>+<span>8
</span></span></span>Combine Like Terms:<span>=<span><span><span><span>8.9x</span>+<span>−5</span></span>+<span>−<span>6.8x</span></span></span>+8</span></span><span>=<span><span>(<span><span>8.9x</span>+<span>−<span>6.8x</span></span></span>)</span>+<span>(<span><span>−5</span>+8</span>)</span></span></span><span>=<span><span>2.1x</span>+<span>3
The simplified answer is </span></span></span><span><span>2.1x</span>+<span>3</span></span>
Answer:
<h2>P(x) = (x+3)(x-2)^2</h2>
Step-by-step explanation:
Looking at the brackets you can see where the curve will intersect the x-axis.
The graph shows the curve intersecting at (0,-3) and (0,2).
This means:
x = -3
AND
x = 2
Rearrange the equations, equating them to 0.
x + 3 = 0
x - 2 = 0
This will be the values in the brackets.
Because the curve only touches 0,2 and DOES NOT cross it, we know that x - 2 is a repeated root, hence (x-2) is squared.
Therefore your brackets are: (x+3)(x-2)(x-2)
Which can be simplified:
(x+3)(x-2)^2
Where ^2 means squared.
Answer:
246.3%
the complete question is found in the attached document
Step-by-step explanation:
1st step:
using 1936 data,
w1= 356% = 3.56(356/100) , H= 79 feet
specific gravity = 2.65
Sₓ= 100%= 1
initial void ratio(e₀)= (w1 x specific gravity)/Sₓ
=3.56 x 2.65/1 = 9.434
2nd step
using 1996 data
ΔH= 22ft
ΔH/H = Δe/(1 + e₀)
22/79 = Δe/(1+9.434)
0.278=Δe/10.434
Δe= 0.278 x 10.434
Δe= 2.905
Δe= e₀ - eₓ
eₓ= e₀-Δe
eₓ= 9.434 - 2.905
eₓ= 6.529
3rd step
calculating water content in 1996
eₓ =6.529, specific gravity= 2.65, Sₓ= 100%
W2 X 2.65 = 1 x 6.529
w2 = 6.529/2.65 = 2.463 = 246.3%
