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Alex787 [66]
3 years ago
9

Which of the following expressions is equal to 5-2m? A. 7-2(m+1)B. 7-(2m-5)C. 7-2(m-2)

Mathematics
2 answers:
Andreas93 [3]3 years ago
8 0
The answer is A to your question
GREYUIT [131]3 years ago
4 0

the answer is option A........

consider expanding into the brackets, helpful?

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A group of 86 people consist of men women and children. There are twice as many women then there are men. There are 6 more child
weqwewe [10]

Answer: 16 men

32 women

38 children

Step-by-step explanation:

Let x represent the number of men in the group.

Let y represent the number if women in the group.

Let z represent the number of children in the group.

A group of 86 people consist of men women and children. This means that

x + y + z = 86 - - - - - - - - - - - - 1

There are twice as many women than there are men. It means that

x = y/2

There are 6 more children than there are women. This means that

z = y + 6

Substituting x = y/2 and z = y + 6 into equation 1, it becomes

y/2 + y + y + 6 = 86

multiplying through by 2, it becomes

y + 2y + 2y + 12 = 172

5y = 172 - 12 = 160

y = 160/5 = 32

x = y/2 = 32/2

x = 16

z = y + 6 = 32 + 6

z = 38

8 0
3 years ago
1........... 5x (3x +2)
babymother [125]

You do 3832083082x 32u393829832983x to get this 5,418

7 0
3 years ago
Please help, fast‍♀️‍♀️
kramer

Inequalities are used to express unequal expressions.

The inequalities from the word problems are:

  • \mathbf{m - 3.5 \le -2}.
  • \mathbf{0 \ge 2x + 1}.
  • \mathbf{-\frac 12 \ge 2k - 4}

The statements from the inequalities are:

  • -4 is not a solution to \mathbf{x + 8 < -3}
  • -6 is not a solution to \mathbf{10 \le 3 - m}
  • -1 is not a solution to \mathbf{-3x \le -12.5}

  • Graph b represents \mathbf{x > -7}

<h3>The word problems</h3>

<u>1. A number minus 3.5 is less than or equal to -2</u>

The statement can be broken down into the following expressions

\mathbf{A\ number\ minus\ 3.5 \to m - 3.5}

\mathbf{less\ than\ or\ equal\ to\ -2 \to \le -2}

So, when the expressions are brought together, we have:

\mathbf{m - 3.5 \le -2}

<u>2. Zero is greater than or equal to twice a number x plus 1</u>

The statement can be broken down into the following expressions

\mathbf{Zero\ is\ greater\ than\ or\ equal\ to \to 0 \ge }

\mathbf{twice\ a\ number\ x\ plus\ 1\  \to 2x + 1}

So, when the expressions are brought together, we have:

\mathbf{0 \ge 2x + 1}

<u />

<u>3. -1/2 is at least twice a number k minus 4</u>

The statement can be broken down into the following expressions

\mathbf{-\frac 12\ is\ at\ least \to -\frac 12 \ge }

\mathbf{twice\ a\ number\ k\ minus\ 4\  \to 2k - 4}

So, when the expressions are brought together, we have:

\mathbf{-\frac12 \ge 2k - 4}

None of the options is correct

<h3>The solutions</h3>

<u>4. Tell whether -4 is a solution to x + 8 < -3</u>

We have:

\mathbf{x + 8

Subtract 8 from both sides

\mathbf{x + 8 - 8

\mathbf{x

The above inequality means that:

<em>x is less than -11</em>

-4 is not a solution, because -4 is greater than -11

<u>5. Tell whether -6 is a solution to 10 <= 3 - m</u>

We have:

\mathbf{10 \le 3 - m}

Subtract 3 from both sides

\mathbf{10 -3\le 3 - 3 - m}

\mathbf{7 \le  - m}

Multiply both sides by -1 (the inequality sign changes)

\mathbf{-7 \ge m}

Make m the subject

\mathbf{m \le -7}

The above inequality means that:

<em>m is less than -7</em>

-6 is not a solution, because -6 is greater than -7

<u>6. Tell whether -1 is a solution to -3x <= -12.5</u>

We have:

\mathbf{-3x \le -12.5}

Divide both sides by -3 (the inequality sign changes)

\mathbf{x \ge 4\frac16}

The above inequality means that:

<em>x is greater than or equal to </em>\mathbf{4\frac16}<em />

-1 is not a solution, because -1 is less than \mathbf{4\frac16}<em />

<h3>The graph</h3>

The inequality is given as: \mathbf{x > -7}

The less than sign (>) means that:

  • The graph would use an open circle
  • The arrow must point to the right

Only graph b satisfies this condition

Hence, the graph of \mathbf{x > -7} is graph b

Read more about inequalities at:

brainly.com/question/15137133

4 0
2 years ago
One day the temperature started -7°F and drop 19° by the end of the day what was the temperature at the end of the day
Kobotan [32]

Answer:-26

Step-by-step explanation: -7 - 19

5 0
3 years ago
What is the exact value of sin(theta + beta)?
NISA [10]

Answer:  \frac{-3\sqrt{13}+4\sqrt{3}}{20}

This is the single fraction of -3*sqrt(13)+4*sqrt(3) up top all over 20.

sqrt = square root

=======================================================

Explanation:

Angle theta is between pi and 3pi/2. This places the angle in quadrant Q3 where both cosine and sine are negative

Use the pythagorean trig identity to get the following:

\sin^2 \theta + \cos^2 \theta = 1\\\\\sin^2 \theta + \left(-\frac{\sqrt{3}}{4}\right)^2 = 1\\\\\sin^2 \theta + \frac{3}{16} = 1\\\\\sin^2 \theta = 1 - \frac{3}{16}\\\\\sin^2 \theta = \frac{16}{16} - \frac{3}{16}\\\\\sin^2 \theta = \frac{16-3}{16}\\\\\sin^2 \theta = \frac{13}{16}\\\\\sin \theta = -\sqrt{\frac{13}{16}} \ \text{ ... sine is negative in Q3}\\\\\sin \theta = -\frac{\sqrt{13}}{\sqrt{16}}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\

Angle beta is in Q1 where sine and cosine are positive.

Draw a right triangle with legs 3 and 4. The hypotenuse is 5 through the pythagorean theorem. In other words, we have a 3-4-5 right triangle.

Since \tan \beta = \frac{3}{4}, this means \sin \beta = \frac{3}{5} \ \text{ and } \ \cos \beta = \frac{4}{5}

Use these ideas:

  • sin = opposite/hypotenuse
  • cos = adjacent/hypotenuse
  • tan = opposite/adjacent

In this case we have: opposite = 3, adjacent = 4, hypotenuse = 5.

-------------------------------------

To recap:

\cos \theta = -\frac{\sqrt{3}}{4}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\\cos \beta = \frac{3}{5}\\\\\sin \beta = \frac{4}{5}\\\\

They lead to this

\sin\left(\theta + \beta\right) = \sin \theta * \cos \beta - \cos \theta * \sin \beta\\\\\sin\left(\theta + \beta\right) = -\frac{\sqrt{13}}{4} * \frac{3}{5} - \left(-\frac{\sqrt{3}}{4}\right) * \frac{4}{5}\\\\\sin\left(\theta + \beta\right) = -\frac{3\sqrt{13}}{20}+\frac{4\sqrt{3}}{20}\\\\\sin\left(\theta + \beta\right) = \frac{-3\sqrt{13}+4\sqrt{3}}{20}\\\\

6 0
2 years ago
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