Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
Answer:
y = -2x + 5
slope = -2
y intercept = 5
Step-by-step explanation:
Slope intercept form of equation of line is given by y = mx + c
where m is the slope of line
c is the y intercept i.e point where given line intersect y axis.
________________________________________________
given equation 4x + 2y = 10
we have to re-write this equation in form y = mx + c
4x + 2y = 10
subtraction 4x from LHS and RHS
4x + 2y - 4x= 10 - 4x
2y = 10- 4x
we have to eliminate 2 from y for that we
divide LHS and RHS by 2 we
2y /2 = 10/2- 4x/2
y = 5 - 2x
rearranging it in y = mx+c form
y = -2x + 5
thus, m = -2 , c = 5
T = Tim, S = Sara, M = Mark
T = 2/3S
S = 3/5M, M = 5/3S
M - 9 = T
5/3S - 9 = 2/3S
S = 9
