Answer:
3 possible prime divisors that go into 420 and 540:
2,3,5
hope this helps!
Step-by-step explanation:
Answer:
give more details
Step-by-step explanation:
Answer: the value of | 2x + y | = 1.39
the direction of 2x + y = 21°
Step-by-step explanation:
Given that the vectors x and y are unit vectors that make and angle of 30 degrees with each other.
Let assume that unit vector x is along the positive x-axis, and unit vector y is at +30°.
Therefore
2x-y=
2< 1,0 > - < cos(30),sin(30) >
=<2-(√2)/2, 0-1/2>
and
|2x-y|=√((2-(√2)/2)² + (-1/2)^2)
=1.3862
Therefore the value of | 2x + y | = 1.39
=atan((-1/2)÷(2-(√2)/2))
=atan(1.29289/-0.5)
=-0.369 radians
= -21.143°
Therefore the direction of 2x + y is
21°
Answer:
2/3 (0,-3) is one possible answer.
Step-by-step explanation:
y -1 = 2/3(x-6) We want to get this into the slope intercept form of a line. We want it to be in the form y = mx + b. Let's clear the fraction first by multiplying the whole equation through by 3.
3(y - 1) = 3[2/3(x - 6)]
3y -3 = 2(x -6)
3y - 3 = 2x -12
3y = 2x - 9 Now divide all the way through by 3 to get
y = 2/3x - 3
y = mx + b. The m part is the slope. In this equation the slope is 2/3
There are in infinite amount of points on a line. I do not know if they give you a picture or if you are just to create your own. I am going to create a point that have x = 0. I get to pick the point. I could pick any number. 0 is just usually really easy. So, if I substitute 0 for x I will get:
y = 2/3(0) - 3
y = 1 so my point is (0,-3)
Now that I think about it, I do not think that I would start out clearing the fraction even though it works. I think that I would do it like this"
y - 1 = 2/3(x - 6) Distribute the 2/3 through (x - 4) to get
y-1 = 2/3x -4 I can make -6 a fraction by putting it over 1. Now we have 2/3(-6/1) multiply across to get -12/3. A positive times a negative is a negative. -12 divided by 3 is -4.
y - 1 = 2/3x -4 now add 1 to both sides.
y = 2/3x -3
Answer:
Option a)
Step-by-step explanation:
To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.
Then. x = 2 it's a vertical asintota.
To obtain the horizontal asymptote of the function take the following limit:
if 
then y = b is horizontal asymptote
Then:
Therefore y = 0 is a horizontal asymptote of f(x).
Then the correct answer is the option a) x = 2, y = 0
