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8 right? Don’t mind this it’s just bc I have to have 29 characters lol.
Answer:

Step-by-step explanation:
Solution:-
- We are given a logistic growth model of the fish population cultured. The logistic growth of fish population is modeled by the following equation:

Where, c: the constant to be evaluated.
- We are given the initial conditions for the model where at t = 0. The initial population was given to be:
t = 0 , Po = 160
N ( carrying capacity ) = 9100
- After a year, t = 1. The population was tripled from the initial value. That is P ( 1 ) = Po*3 = 160*3 = 480.
- We will use the given logistic model and set P ( 1 ) = 480 and determine the constant ( c ) as follows:
![P ( 1 ) = \frac{c}{1 + 55.875e^-^ 1^.^1^3^5^0^6^*^1} = 480\\\\c = 480* [ 1 + 55.875e^-^ 1^.^1^3^5^0^6]\\\\c = 9100.024](https://tex.z-dn.net/?f=P%20%28%201%20%29%20%3D%20%5Cfrac%7Bc%7D%7B1%20%2B%2055.875e%5E-%5E%201%5E.%5E1%5E3%5E5%5E0%5E6%5E%2A%5E1%7D%20%3D%20480%5C%5C%5C%5Cc%20%3D%20480%2A%20%5B%201%20%2B%2055.875e%5E-%5E%201%5E.%5E1%5E3%5E5%5E0%5E6%5D%5C%5C%5C%5Cc%20%3D%209100.024)
- The complete model can be written as:

Area of a trapezoid is height times the average of the bases,
A= 1/2 h (a + b)
Here we have height h=12 and bases a=30, b=12 so area
A = (1/2) (12) (30 + 12) = 6(42)= 252
Answer: B
5,400 is the answer to the question that you have asked