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aalyn [17]
3 years ago
7

Can yall check my answer ?

Mathematics
2 answers:
Rzqust [24]3 years ago
6 0

Answer:

its good :)

Step-by-step explanation:

coldgirl [10]3 years ago
5 0
Perfect please take a cookie
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Biologists stock a lake with 160
Nutka1998 [239]

Answer:

P ( t ) = \frac{9100.024}{1 + 55.875e^-^1^.^1^3^5^0^6^*^t}

Step-by-step explanation:

Solution:-

- We are given a logistic growth model of the fish population cultured. The logistic growth of fish population is modeled by the following equation:

                         P ( t ) = \frac{c}{1 + 55.875e^-^ 1^.^1^3^5^0^6^t}

Where,        c: the constant to be evaluated.

- We are given the initial conditions for the model where at t = 0. The initial population was given to be:

t = 0 ,              Po = 160

                       N ( carrying capacity ) = 9100

- After a year, t = 1. The population was tripled from the initial value. That is P ( 1 ) = Po*3 = 160*3 = 480.

- We will use the given logistic model and set P ( 1 ) = 480 and determine the constant ( c ) as follows:

                           P ( 1 ) = \frac{c}{1 + 55.875e^-^ 1^.^1^3^5^0^6^*^1} = 480\\\\c = 480* [ 1 + 55.875e^-^ 1^.^1^3^5^0^6]\\\\c = 9100.024

- The complete model can be written as:

                            P ( t ) = \frac{9100.024}{1 + 55.875e^-^1^.^1^3^5^0^6^*^t}

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A = (1/2) (12) (30 + 12) = 6(42)= 252

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5,400 is the answer to the question that you have asked
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