Answer:
Milford location has a higher ratio of hamsters to gerbils.
Step-by-step explanation:
Given:
A pet supply chain called Pet City has 5 hamsters and 10 gerbils for sale at its Lanberry location.
At its Milford location, there are 13 hamsters and 16 gerbils.
Now, to find the location who has a higher ratio of hamsters to gerbils.
Ratio of hamsters to gerbils at Lanberry location = 5:10.
![=\frac{5}{10}=0.50](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5%7D%7B10%7D%3D0.50)
Ratio of hamsters to gerbils at Milford location= 13:16.
![=\frac{13}{16} =0.8125](https://tex.z-dn.net/?f=%3D%5Cfrac%7B13%7D%7B16%7D%20%3D0.8125)
<em>So, 0.8125 > 0.50.</em>
<em>Thus, </em><u><em>13:16 > 5:10.</em></u><em> </em>
Therefore, Milford location has a higher ratio of hamsters to gerbils.
3 cups=24 fl oz.
1 cups is 8 oz.
Answer: Mass of Lamina is (K/3)
Centre of mass is (3/8, 3pi/16)
Step-by-step explanation:
Find explanation in the attachments
Answer:
6.9 in²
Step-by-step explanation:
(4×8)-(2×3.14×2²)
= 32 - 25.12
= 6.9
<h3><u>Question:</u></h3>
A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula represents the volume of the pyramid?
<h3><u>Answer:</u></h3>
<em><u>The formula represents the volume of the pyramid is:</u></em>
![V=\frac{1}{6}s^3](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B6%7Ds%5E3)
<h3><u>Solution:</u></h3>
<em><u>The volume of square pyramid is given by formula:</u></em>
![V = \frac{1}{3} a^2h](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20a%5E2h)
Where, "h" is the height of pyramid
"a" is the length of side of base
Here given that, pyramid has a square base with sides of length s
Therefore,
a = s
The height of the pyramid is equal to 1/2 of the length of a side on the base
![h = \frac{1}{2} \times s\\\\h = \frac{s}{2}](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%20s%5C%5C%5C%5Ch%20%3D%20%5Cfrac%7Bs%7D%7B2%7D)
<em><u>Thus the volume of pyramid becomes:</u></em>
![V = \frac{1}{3} \times s^2 \times \frac{s}{2}\\\\V = \frac{s^3}{6}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B3%7D%20%5Ctimes%20s%5E2%20%5Ctimes%20%5Cfrac%7Bs%7D%7B2%7D%5C%5C%5C%5CV%20%3D%20%5Cfrac%7Bs%5E3%7D%7B6%7D)
![\boxed{V=\frac{1}{6}s^3}](https://tex.z-dn.net/?f=%5Cboxed%7BV%3D%5Cfrac%7B1%7D%7B6%7Ds%5E3%7D)
Thus the formula represents the volume of the pyramid is ![\frac{s^3}{6}](https://tex.z-dn.net/?f=%5Cfrac%7Bs%5E3%7D%7B6%7D)