Answer:
72.50/100 X 80 = 58
total cost with mark down $58
There are four aces, 12 face cards and 4 7s in a standard 52 card deck. The probability of getting an ace on the first draw is 4/52 or 1/13. For the second draw there are now 51 cards in the deck (assuming the draws are without replacement), so the probability of getting a face card is 12/51. Given an ace and a face card on the first two draws, the probability of a 7 on the third draw is 4/50 or 2/25. The probability of getting all three is 1/13*12/51*2/25.
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Related Questions (More Answers Below)
Answer:
Measurement of OP = 12
Step-by-step explanation:
Given:
R is mid point of OQ
S is mid point of PQ
RS = 18 – 4x
OP = -9 + 7x
Find:
Measurement of OP
Computation:
R is mid point of OQ and S is mid point of PQ;
By using mid point theorem
[1/2][OP] = RS
So,
[1/2][-9 + 7x] = [18 - 4x]
[-9 + 7x] = 2[18 - 4x]
-9 + 7x = 36 - 8x
7x + 8x = 36 + 9
15x = 45
x = 45 / 15
x = 3
So,
OP = -9 + 7x
OP = -9 + 7(3)
Measurement of OP = 12
Answer:
Hello! Here is your answer
Step-by-step explanation:
112=4(28)
a=4b
You can only have one variable so:
Combine b to a:
a-b=84
4b-b=84
Divide both sides by 3:
3b/3=84/3
b=28
But that is not it:
Sum of both cards:
a+b
a=112
b=28
112+28=140
= 140
I hope I was of help. If not please let me know! Thank you! Good luck!
