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2 years ago

Okay, I'm going to be adding more but what is 4/10 x 3?

Mathematics

2 answers:

soldier1979 [14.2K]2 years ago

5 0

Answer:

6/5 or 1.2

I am from India,

please Upvote and Mark as Brainliest if you like.

Marat540 [252]2 years ago

4 0

Answer:

6/5 or 1 1/5

6/5 is an improper fraction, so I didnt know if youd need an improper one or a proper one. They both are the same thing though :)

Step-by-step explanation:

4/10*3

They both need to be a fraction, and any number over 1 = that number. So,

4/10*3/1

4*3=12

10*1=10

12/10

Then, you have to simplify the fraction.

6/5 (bc 2 goes into 12 6 times and 2 goes into 10 5 times)

or 1 2/10= 1 1/5

Hope this helps. Plz give brainliest. Also, plz sub to Kgirl633 on yt.

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The difference of the square of a number and 10 is equal to 3 times that number. Find the negative solution.

Harrizon [31]

Answer:

-2

Step-by-step explanation:

Let's call the number x. The statement tells us that

x^2 - 10 = 3x, or

x^2-3x-10 = 0

Factoring:

(x-5)(x+2) = 0. Here, we see that there are two solutions: x = 5 and x = -2. So, the negative solution is x = -2.

3 0

2 years ago

∠R and ∠S are complementary. If m∠R = (2x+7) and m∠S = (4x - 13), find m∠R

____ [38]

Answer:

m∠R = 39 degrees

Step-by-step explanation:

As complementary angles add up to 90 degrees, we can set up an equation to get x then find the measure of ∠R:

m∠R + m∠S = 90

2x+7+4x-13=90

6x+7-13=90

6x-6=90

6x=96

x=16

Since m∠R = (2x+7), 2x+7 would be 2(16)+7 or 39 degrees. So in conclusion, m∠R = 39 degrees

3 0

3 years ago

Read 2 more answers

A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1200 hours and a standar

a_sh-v [17]

Answer:

The bulbs should be replaced each 1060.5 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1200, \sigma = 60$