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GenaCL600 [577]
3 years ago
7

Scarlett made 1/2 of a recipe and used 4/5 cups of bananas. How many cups of bananas are required for a whole recipe??

Mathematics
2 answers:
Flura [38]3 years ago
8 0
I think that it is 0.4
docker41 [41]3 years ago
5 0

Answer:

I'm pretty sure the answer would be 2/5

Step-by-step explanation:

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PLZZ HELP
9966 [12]

An arithmetic sequence would have a common difference between successive terms, not the case here.

A geometric sequence has a common ratio; let's check:

\dfrac{1/2}{1/6} = 3

\dfrac{3/2}{1/2} = 3

\dfrac{9/2}{3/2} = 3

That's a common ratio of 3 so as far as we can tell a geometric sequence.

Answer: geometric

3 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!! WILL MARK BRAINLIEST ANSWER.
Hatshy [7]
.033333
3/100


Hopes this helps! :)
3 0
3 years ago
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A gas engine is 6% efficient. What portion of a 12 gallon tank of gas is wasted?
Softa [21]

Answer:19.74 gallons of the gas in the tank is wasted.

Step-by-step explanation:

Since the efficiency of the gas engine is 6%, wastage is #= 100 - 6 = 94%.

Therefore wastage = 94% x 21=94 x21/100=19.74 gallons

5 0
3 years ago
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Solve for x <br> A) 12 <br> B) 11<br> C) 8 <br> D) 10
Furkat [3]

Answer:

B i would be good i solve 20 minutes

6 0
3 years ago
What is the solution to the following system?
leva [86]

Answer:

(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

\left[\begin{array}{cccc}3&2&1&20\\1&-4&-1&-10\\2&1&2&15\end{array}\right]

Now I will shift rows to make my pivot point (top left) a 1 and so:

\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

Next I will come up with algorithms that can cancel out numbers where R1 means row 1, R2 means row 2 and R3 means row three therefore,

-2R1+R2=R2 , -3R1+R3=R3

\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

\frac{R_2}{9}=R_2


\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

7 0
3 years ago
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