All categories

3 years ago

Scarlett made 1/2 of a recipe and used 4/5 cups of bananas. How many cups of bananas are required for a whole recipe??

Mathematics

2 answers:

Flura [38]3 years ago

8 0

I think that it is 0.4

docker41 [41]3 years ago

5 0

Answer:

I'm pretty sure the answer would be 2/5

Step-by-step explanation:

You might be interested in

jeanine Baker makes floral arrangements. She has 13 different cut flowers and plans to use 7 of them. How many different selecti

Ksju [112]

A total of 1,716 selections of the 7 flowers are possible.

Step-by-step explanation:

Step 1:

There are 13 flowers from which Jeanine Baker plans to use 7 of them.

To determine the number of selections that are possible we use combinations.

The formula for combinations is; $^{n} C_{r}=\frac{n !}{(n-r) ! r !}$ .

Step 2:

In the given formula, n is the total number of options and r is the number of options to be selected.

For this question, $n = 13$ and $r=7$ .

So $^{13} C_{7}=\frac{13 !}{(13-7) ! 7 !} = \frac{13 !}{(6) ! 7 !} = 1,716.$

So a total of 1,716 selections are possible.

3 0

3 years ago

At the city museum, child admission is $5.80 and adult admission is $9.60. On Friday, three times as many adult tickets as child

noname [10]

Its 74 and if its wrong im sorry but hi

7 0

3 years ago

Select the best answer for the question. 8. Evaluate m + n2 if we know m = 2 and n = –2. A. –6 B. 6 C. 8 D. –8

natta225 [31]

M + n² = (2) + (-2)² = 2 + 4 = 6

Answer: 6

3 0

3 years ago

When grading an exam, 90% of a professor's 50 students passed. If the professor randomly selected 10 exams, what is the probabil

Damm [24]

Using the binomial distribution, it is found that there is a:

a) 0.9298 = 92.98% probability that at least 8 of them passed.

b) 0.0001 = 0.01% probability that fewer than 5 passed.

For each student, there are only two possible outcomes, either they passed, or they did not pass. The probability of a student passing is independent of any other student, hence, the binomial distribution is used to solve this question.

<h3>What is the binomial probability distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

90% of the students passed, hence $p = 0.9$ .

The professor randomly selected 10 exams, hence $n = 10$ .

Item a:

The probability is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.9)^{8}.(0.1)^{2} = 0.1937$

$P(X = 9) = C_{10,9}.(0.9)^{9}.(0.1)^{1} = 0.3874$

$P(X = 10) = C_{10,10}.(0.9)^{10}.(0.1)^{0} = 0.3487$

Then:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1937 + 0.3874 + 0.3487 = 0.9298$

0.9298 = 92.98% probability that at least 8 of them passed.

Item b:

The probability is:

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Using the binomial formula, as in item a, to find each probability, then adding them, it is found that:

$P(X < 5) = 0.0001$

Hence:

0.0001 = 0.01% probability that fewer than 5 passed.

You can learn more about the the binomial distribution at brainly.com/question/24863377

3 0

2 years ago

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

MAVERICK [17]

Answer:

Step-by-step explanation:

3rd one

3 0

3 years ago