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allochka39001 [22]
3 years ago
10

I am not very good at angles please help me.

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

∠3 and ∠7 ↔ Corresponding Angles

∠2 and ∠7 ↔ Alternate Exterior Angles

∠4 and ∠5 ↔ Alternate Interior Angles

∠3 and ∠6 ↔ Alternate Interior Angles

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The pair of points (-4, y) and (5, 7) lie on a line with slope . What is the value of y? You must show all of your work to recei
Svetach [21]

The slope of a line is given by the ratio of the rise to the run of the line.

The value of, y is <u>4</u>

Reasons:

The given points on the line are; (-4, y), and (5, 7)

The slope of the line, = \dfrac{1}{3}

Required:

To find the value of <em>y</em>

<em />

Solution:

The formula for the slope is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where;

(x₁, y₁) = (-4, y)

(x₂, y₂) = (5, 7)

Which gives;

Slope, \, m =\dfrac{7-y}{5-(-4)} = \dfrac{7-y}{5+4} =\dfrac{1}{3}

3·(7 - y) = 1·(5 + 4) = 9

21 - 3·y = 9

3·y = 21 - 9 = 12

y = \dfrac{12}{3} = 4

The value of, y = <u>4</u>

Learn more here:

brainly.com/question/1617757

8 0
3 years ago
The gcf of 15 and 27 is ____.
Vlad1618 [11]
The greatest common factor of 15 and 27 is 3
5 0
4 years ago
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Need help with my trig homework
dalvyx [7]

The 30º-60º-90º triangle is a special case you'd do well to remember, because the legs always occur in the same ratio to one another. As your picture shows (I'm guessing "SL" stands for short leg?), the sides labeled 4, y and x occur in a ratio of 1 to √3 to 2.

This means

sin(30º) = SL/(2*SL) = 1/2

tan(30º) = SL/(√3*SL) = 1/√3

(and also cos(30º) = (√3*SL)/(2*SL) = √3/2, though you don't really need that here)

So in this triangle, x and y satisfy

sin(30º) = 4/x

tan(30º) = 4/y

This comes straight from the definitions of sine and tangent. Then

4/x = 1/2  ==>  x = 8

4/y = 1/√3  ==>  y = 4√3

8 0
3 years ago
The points (3,-2) and (2, 1) are both solutions to which inequality?
KIM [24]

(3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<h3>How to determine the inequality?</h3>

The complete question is added as an attachment

The points are given as:

(3, -2) and (2, 1)

Next, we test the points on each inequality in the list of options.

So, we have:

<u>Option 1</u>

y > 1/2x + 2

Substitute (3, -2) and (2, 1) for x and y

-2 > 1/2 * 3 + 2 ⇒ -2 > 3.5 -- false

2 > 1/2 * 1 + 2 ⇒ 2 > 2.5 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y > 1/2x + 2

<u>Option 2</u>

y <= 3/2x - 1

Substitute (3, -2) and (2, 1) for x and y

-2 <= 3/2 * 3 - 1 ⇒ -2 <= 3.5 -- true

1 <= 3/2 * 2 - 1 ⇒ 1 < 2 -- true

Hence, (3, -2) and (2, 1) are solutions to the inequality y <= 3/2x - 1

<u>Option 3</u>

y >= 4x - 2

Substitute (3, -2) and (2, 1) for x and y

-2 >= 4 * 3 - 2 ⇒ -2 >= 10 -- false

2 <= 4 * 2 - 2 ⇒ 2 <= 6 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y >= 4x - 2

<u>Option 4</u>

y < -2x + 1

Substitute (3, -2) and (2, 1) for x and y

-2 < -2 * 3 + 1 ⇒ -2 < -5 -- false

2 < -2 * 2 + 1 ⇒ 2 < -3 -- false

Hence, (3, -2) and (2, 1) are not solutions to the inequality y < -2x + 1

Read more about inequality at

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7 0
2 years ago
Suppose a laboratory has a 38 g sample of polonium-210. The half-life of polonium-210 is about 138 days. How many half-lives of
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To find the number of half lives divide the total number of days by the number of days for 1 half live:

1104 / 138 = 8

There are 8 half lives.

To find the total amount left multiply the starting amount by 1/2 to the 8th power:

38 * 0.5^8 = 0.148 = 0.15 grams

The answer is the last one.
6 0
3 years ago
Read 2 more answers
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