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3 years ago

Need help ASAP, I am really confused!

Mathematics

1 answer:

guajiro [1.7K]3 years ago

4 0

x=2 and y = 6 for your awnser hope it helped

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Which graph shape represents the polar curve r = 1 + 4sin(θ)?

umka2103 [35]

Answer:

A cardioid

Step-by-step explanation:

A cardioid is a curve in the shape of a heart traced by a point on the circumference of a circle as it rolls around a fixed circle of the same radius.

The equation of vertical cardioid is $r=a$ ± $a\sin \theta$

Given the polar curve is $r=$ $1+$ 4 $\sin \theta$

This is an equation of vertical cardioid.

So, it represents a cardioid.

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3 years ago

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2 2/10 x 6 2/5 please help me!!!!! Thank you!!!

evablogger [386]

The answer is 24/25.

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3 years ago

(05.03)An irregular polygon is shown below:

SVEN [57.7K]

9units sorry for not showing work though but glad I can help

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3 years ago

Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*

dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\$

$5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\$

$\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3$

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3 years ago

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Look at the image and please help.

dem82 [27]

How do we help u??? we can’t graph for u

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3 years ago