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victus00 [196]
3 years ago
14

Write an equation of the parabola in vertex form.

Mathematics
2 answers:
egoroff_w [7]3 years ago
7 0

Answer:

y =0.25(x-4 )^{2}-1

Step-by-step explanation:

The formula of vertex form is as follows:

Y = a(x-h)^2+k

h = the x value for the vertex (in this case it is 4)

k = the y value for the vertex (in this case it is -1)

If you input these into the equation you are left with:

Y = a(x-4)^2-1

To find 'a' I just entered this equation into the Desmos calculator and messed around with the value until the y-intercept was (8,3)

I hope this was able to help! ^_^

Katena32 [7]3 years ago
6 0

Answer:

f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. ... When written in "vertex form": • (h, k) is the vertex of the parabola, and x = h is the axis of symmetry.

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Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.
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Answer:

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Step-by-step explanation:

Given homogeneous equation

x^2ydy+xy^2dx=0

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Substitute y=ux , u=\frac{y}{x}

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}

Now,

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u

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Substitute u=\frac{y}{x}

Then we get

xy=C

y=\frac{C}{x}.

Answer:y=\frac{C}{x}.

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