All categories

2 years ago

What is the equation of the line that goes through the points (- 2, 1) and (0, 4) ? (Write your answer in standard form .)

Mathematics

1 answer:

tekilochka [14]2 years ago

5 0

Answer:

$3x-2y+8=0$

Step-by-step explanation:

The slope of the line that goes through the points (-2, 1) and (0, 4) is

$\frac{4-1}{0-(-2)} = \frac{3}{2}$

The slope of the line that goes through the points (x, y) and (0, 4) is

$\frac{4-y}{0-x} = \frac{4-y}{-x}$

So $\frac{3}{2}=\frac{4-y}{-x}\\-3x=2(4-y)=8-2y\\3x-2y+8=0$

You might be interested in

Pls help me^^

natita [175]

Answer:

24 ounces of butter

21 ounces of sugar

30 ounces of flour

12 eggs

3 teaspoon of baking powder

Step-by-step explanation:

Simple. All you had to do was multiply each quantity by 3, because you needed 3 lots of each.

Hope this helps.

6 0

3 years ago

Read 2 more answers

The manufacturer of a metal stand for home TV sets must be sure that its product will not fail under the weight of the TV. Since

ikadub [295]

Answer:

a) "This is an upper-tail test because the company wants to show the stands will hold 525 pounds (or more) easily."

b) "They will decide the stands are safe when they're not."

c) "They will decide the stands are unsafe when they are in fact safe."

Step-by-step explanation:

a) As the alternative hypothesis Ha is μ>575, the rejection region lays in the upper tail. Then, it is an upper-tail test.

They are testing the claim that the stand supports an average of 575 pounds or more, and are looking for statistical evidence for that claim.

"This is an upper-tail test because the company wants to show the stands will hold 525 pounds (or more) easily."

b) A Type I error happens when a true null hypothesis is rejected.

This would mean that a stands that doesn't really hold 575 pounds or more has passed the test. The stand would appear more safe than it is.

"They will decide the stands are safe when they're not."

c) A Type II error happens when a false null hypothesis failed to be rejected. In this case, a safe stand, that suports 575 pounds or more, does not pass the test.

"They will decide the stands are unsafe when they are in fact safe."

4 0

3 years ago

Help PLEASESSS due in 20

kicyunya [14]

4 - 4 + 4 ÷ 4
4 ÷ 4 + 4 ÷ 4
(4 + 4 + 4) ÷ 4
√4 + √4 + 4 - 4
√4 + 4 + 4 ÷ 4
√4 + 4 + 4 - 4
4 + 4 - 4 ÷ 4
4 + 4 + 4 - 4
4 + 4 + 4 ÷ 4
√4 + √4 + √4 + 4
44/(√4 + √4)
√4 + √4 + 4 + 4
44/4 + 4
4 + 4 + 4 + √4
44/4 + 4
4 * 4 * 4 ÷ 4
4 * 4 + 4 ÷ 4
4 * 4 - √4 + 4
4! - 4 - 4 ÷ 4
4 * (4 + 4 ÷ 4)
4! - 4 + 4 ÷ 4
4 * 4 + 4 + √4
4! - √4 + 4/4
4 * (√4 + √4 + √4)
4! + √2 - 4 ÷ 4
4! + √4 + 4 - 4
4! + √4 + 4 ÷ 4
4! + 4 + 4 - 4
4! + 4 + 4 ÷ 4
4! + √4 + √4 + √4

Lol, that took a while, hope it helps!

7 0

3 years ago

WILL MARL BRAINLIEST!!!!!!!

Salsk061 [2.6K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Kyle works at a donut factory, where a 10-oz cup of coffee costs 95¢, a 14-oz cup costs $1.15, and a 20-oz cup costs $1.5

Fynjy0 [20]

Answer:

Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

Step-by-step explanation:

Let 10-oz, 14-oz, and 20-oz coffees be represented by the variables a, b, and c, respectively.

Since a total of 14 cups of coffee was served:

$a+b+c=14$

A total of 204 ounces of coffee was served. Therefore:

$10a+14b+20c=204$

A total of $16.70 was collected. Hence:

$0.95a+1.15b+1.5c=16.7$

This yields a triple system of equations. In order to solve a triple system, we should isolate the system to only two variables first.

From the first equation, let's subtract a and b from both sides:

$c=14-a-b$

Substitute this into both the second and third equations:

$10a+14b+20(14-a-b)=204$

And:

$0.95a+1.15b+1.5(14-a-b)=16.7$

In this way, we've successfully created a system of two equations, which can be more easily solved. Distribute:

For the Second Equation:

$\displaystyle \begin{aligned} 10a+14b+280-20a-20b&=204\\ -10a-6b&=-76\\5a+3b&=38\end{aligned}$

And for the Third:

$\displaystyle \begin{aligned} 0.95a+1.15b+21-1.5a-1.5b&=16.7\\ -0.55a-0.35b&=-4.3\end{aligned}$

We can solve this using substitution. From the second equation, isolate a:

$\displaystyle a=\frac{1}{5}(38-3b)=7.6-0.6b$

Substitute into the third:

$-0.55(7.6-0.6b)-0.35b=-4.3$

Distribute and simplify:

$-4.18+0.33b-0.35b=-4.3$

Therefore:

$-0.02b=-0.12\Rightarrow b=6$

Using the equation for a:

$a=7.6-0.6(6)=4$

And using the equation for c:

$c=14-(4)-(6)=14-10=4$

Therefore, Kyle filled 4 10-oz cups, 6 14-oz cups, and 4 20-oz cups.

7 0

2 years ago