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ASHA 777 [7]
3 years ago
12

The most commonly used video formats are the mpeg-____ format, the windows media audio/video format, and the audio visual interl

eave format.
Computers and Technology
1 answer:
Archy [21]3 years ago
8 0
<span>The answer is mpeg-4.  The most commonly used video formats are the mpeg-4 format, the windows media audio/video format, and the audio visual interleave format.</span>
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Need Help ASAP!
jonny [76]

Answer:

Ask about next steps and the best way to communicate.

Send a follow-up email within 24 hours.

Explanation:

3 0
3 years ago
Read 2 more answers
The valid call to the function installApplication is
Zanzabum

Answer:

B. installApplication(‘A’, 1);

Explanation:

Given

The above code segment

Required

The correct call to installApplication

The function installApplication is declared as void, meaning that it is not expected to return anything.

Also, it receives a character and an integer argument.

So, the call to this function must include a character and an integer argument, in that order.

Option D is incorrect because both arguments are integer

Option C is incorrect because it passes no argument to the function.

Option A is incorrect because it receives an integer value from the function (and the function is not meant not to have a return value).

Option B is correct

8 0
3 years ago
Write a program that will open the file random.txt and calculate and display the following: A. The number of numbers in the file
Rama09 [41]

Answer:

Here is the C++ program:

#include <iostream>  //to use input output functions

#include <fstream>  //to manipulate files

using namespace std;  //to identify objects like cin cout

int main(){  //start of main function

  ifstream file;   //creates an object of ifstream

   file.open("random.txt"); //open method to open random.txt file using object file of ifstream

       

    int numCount = 0;  //to store the number of all numbers in the file          

    double sum = 0;   //to store the sum of all numbers in the file

    double average = 0.0;   //to store the average of all numbers in the file

    int number ; //stores numbers in a file

                 

        if(!file){   //if file could not be opened

           cout<<"Error opening file!\n";    }   //displays this error message

       

       while(file>>number){   //reads each number from the file till the end of the file and stores into number variable

           numCount++; //adds 1 to the count of numCount each time a number is read from the file          

           sum += number;  }  //adds all the numbers and stores the result in sum variable

           average = sum/numCount;  //divides the computed sum of all numbers by the number of numbers in the file

     

       cout<<"The number of numbers in the file: "<<numCount<<endl;  //displays the number of numbers

       cout<<"The sum of all the numbers in the file: "<<sum<<endl;  //displays the sum of all numbers

       cout<<"The average of all the numbers in the file: "<< average<<endl;  //displays the average of all numbers

       file.close();     }  //closes the file    

   

Explanation:

Since the random.txt is not given to check the working of the above program, random.txt is created and some numbers are added to it:

35

48

21

56

74

93

88

109

150

16

while(file>>number) statement reads each number and stores it into number variable.

At first iteration:

35 is read and stored to number

numCount++;  becomes

numCount = numCount + 1

numCount = 1      

sum += number; this becomes:

sum = sum + number

sum = 0 + 35

sum = 35

At second iteration:

48 is read and stored to number

numCount++;  becomes

numCount = 1+ 1

numCount = 2    

sum += number; this becomes:

sum = sum + number

sum = 35 + 48

sum = 83

So at each iteration a number is read from file, the numCount increments to 1 at each iteration and the number is added to the sum.

At last iteration:

16 is read and stored to number

numCount++;  becomes

numCount = 9 + 1

numCount = 10    

sum += number; this becomes:

sum = sum + number

sum = 674 + 16

sum = 690

Now the loop breaks and the program moves to the statement:

       average = sum/numCount;  this becomes:

       average = 690/10;

       average = 69

So the entire output of the program is:

The number of numbers in the file: 10                                                                                                           The sum of all the numbers in the file: 690                                                                                                     The average of all the numbers in the file: 69

The screenshot of the program and its output is attached.

5 0
3 years ago
Question :
BlackZzzverrR [31]

Answer:

D

Explanation:

Search engine optimization (SEO)

4 0
3 years ago
1. A teacher asked a student to capture and print out a one-slide presentation using MSWord,       showing everything on the scr
Drupady [299]

The keyboard combinations that can be used to capture and print out a one-slide presentation using MSWord, showing everything on the screen is Function key + PrtScr

<h3>What is a Key Combination?</h3>

This refers to the procedure that is used to combine two or more keys on the keyboard to execute a task.

Hence, we can see that the procedure that can be used to carry out the operation is:

  • Enter the screen you want to capture and print
  • Press the Function key, followed by the PrtScr. Please note this can vary slightly, depending on the keyboard.

The hardware devices that would be needed to be set up by the system analyst at a computer laboratory are:

  • System Unit
  • Laptops/Monitor
  • Power adapters
  • Ethernet cables, etc

The database applications that can be recommended by the system analyst are:

  • MySQL,
  • SQL Server

The five word processing packages that are likely to be installed are:

  • G00..gle Docs
  • MsWord
  • MSOffice
  • Dropbox Paper
  • Corel WordPerfect

Read more about word processing here:

brainly.com/question/985406

#SPJ1

6 0
2 years ago
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