brackets, exponents, division, multiplication, addition, and subtraction
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Answer:
International Medical Informatics Association (IMIA)
Explanation:
In respect of the question which askabout the organization who play an important role in regards to the development of global health informatics is International Medical Informatics Association (IMIA).
International Medical Informatics Association (IMIA) which is an interni association which are independent which works toward expanding and sustaining of global Biomedical and Health Informatics community and give maximum support to international initiative which are geared towards providing adequate and standardized health for each and everyone in the world at large.
