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2 years ago

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Steven’s mother asked him to buy 750 grams of sugar. At the supermarket, he finds that the sugar packages give the weight in kil

ograms. What is the amount of sugar in kilograms that Steven needs to buy?

1 answer:

9966 [12]2 years ago

7 0

1, 000 grams = 1 kg
(divide both sides by 1, 000)
1 gram = 1/1, 000 kg
750 grams = 750 x (1/1000) kg = 0.75 kg

Therefore, Steven needs to buy 0.75 kg of sugar!

hope this helps! let me know if you need help with anything else! :)

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Write 77.5% as a fraction or mixed number in simplest form.

Delicious77 [7]

Answer:

The answer is $77\frac{1}{2}$ .

Step-by-step explanation:

Given:

77.5%.

Now, to write as a fraction or mixed number in simplest form.

77.5%

So, we divide by 10 by removing decimal as decimal is at tenth place.

= $\frac{775}{10}$

So, simplifying it:

$=\frac{155}{2}$

Now, we change into mixed fraction:

$=77\frac{1}{2}$

Therefore, the answer is $77\frac{1}{2}$ .

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2 years ago

PLEASE HELP Complete the table below to find solutions to the linear equation y=5x+35.

Eddi Din [679]

Answer:

x | y | (x,y)

0 | 35 | (0,35)

3 | 50 | (3,50)

-7 | 0 | (-7,0)

Step-by-step explanation:

Given the equation: $y = 5x + 35$ , to complete the table, plug in the value of x given in the table in each row, to find y.

When x = 0,

$y = 5(0) + 35$

$y = 0 + 35$

$y = 35$

(0,35)

When x = 3,

$y = 5(3) + 35$

$y = 15 + 35$

$y = 50$

(3,50)

When x = -7,

$y = 5(-7) + 35$

$y = -35 + 35$

$y = 0$

(-7,0)

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2 years ago

There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?

Andrei [34K]

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒ $\text{Male students} +\text{Female students} = 15$ ....[1]

It is given that:

40% of the students are females

⇒ $\text{Female students} = \frac{40}{100} \cdot 15 = 6$

Substitute in [1] we have;

$\text{Male students} + 6 = 15$

Subtract 6 from both sides we have;

$\text{Male students}= 9$

Therefore, 9 students on the committee are males

8 0

3 years ago

Read 2 more answers

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

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2 years ago

triangle ABC is isosceles, angle B is vertex angle , AB = 20x -2, AC =25x, and BC =12 x +20. Find x and the length of each side

lisov135 [29]

Length of AB = 18. 92

Length of AC = 26. 15

Length of BC = 32. 552

<h3>How to determine the sides of the triangle</h3>

Using the Pythagorean theorem, we have that

$(20 x-2)^2 = (12x + 20)^2 + (25x)^2$

Expand the bracket

$400x^2- 4 = 144x^2 + 400 + 625x^2$

Collect like terms

$400x^2 - 144x^2 - 625x^2 = 400 + 4$

$-369x^2 = 404$

Make x^2 subject

$x^2 = \frac{404}{369}$

$x = \sqrt{1.0948}$

$x = 1. 046$

Thus,

Length of AB = 20x -2 = 20(1. 046) - 2 = 18. 92

Length of AC = 25x = 25* 1.046 = 26. 15

Length of BC = 12x + 20 = 12(1. 046) + 20 = 32. 552

Learn more about isosceles triangles here:

brainly.com/question/1475130

#SPJ1

8 0

1 year ago