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kirill [66]
3 years ago
7

Rashida had 18 correct answers and 12 incorrect anwesrs what was rashida score

Mathematics
2 answers:
romanna [79]3 years ago
7 0

Answer:

rashid score = 18/(18+120=18/30

Step-by-step explanation:

melisa1 [442]3 years ago
4 0

Answer:

hi

Step-by-step explanation:

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Help pls
maw [93]

Answer:

Step-by-step explanation:

6x+3 -6x =3

6x-6x= 3-3

0 = 0

4 0
3 years ago
The low temperatures for a week in winter were -2° F, -15° F, -7° F, 1° F, -4° F, 5° F, 8° F. What was the average low
Novay_Z [31]

Answer: -2 F

Step-by-step explanation:

To find the average, or <em>mean, </em>of a data set, you must first combine all of the values in the set. Since some of these values are negative, it seems more difficult to solve. But it isn't. To find the mean of any data sets, you can find the absolute value of each numerical value. If you combine these regularly, it would be -15, but that is incorrect. The answer is -2 because some of the values may be negative, but you can find the answer easily. Just remember: To find the mean of data sets with negative values, you can find their absolute values, and solve from there. If this does not work for you, then find another solution. But the correct answer is -2 F.

3 0
3 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
I need help please?!!!!!!
Vadim26 [7]

Answer:

simplified is

x ^5 y ^15 z ^10

Step-by-step explanation:

3 0
4 years ago
Which polynomial is the product of (4x+1) and (3x+2)?
maria [59]
(4x+1)(3x+2)\\\\=4x \times 3x+4x \times 2 + 1 \times 3x + 1 \times 2\\\\ = 12x^2+8x+3x+2\\\\ = 12x^2+11x+2

Answer A
8 0
3 years ago
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