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dolphi86 [110]
3 years ago
11

The function A(b) relates the area of a trapezoid with a given height of 14 and one base length of 5 with the length of its othe

r base. It takes as input the other base value, and returns as output the area of the trapezoid. A(b)=14xb+5/2 Which equation below represents the inverse function B(a), which takes the trapezoid's area as input and returns as output the length of the other base? A. B(a)+a/7+5 B. B(a)=a/5-7 C. B(a)=a/7-5 D. B(a)=a/5+7
Mathematics
1 answer:
Brut [27]3 years ago
4 0

Answer:

b(a) =\frac{a}{7} -5

Step-by-step explanation:

Given

A(b) = 14 * \frac{b + 5}{2}

Required

Determine the inverse function b(a)

Write A(b) as a

a = 14 * \frac{b + 5}{2}

Swap a and b

b = 14 * \frac{a + 5}{2}

b = 7(a + 5)

Divide both sides by 7

a + 5 = \frac{b}{7}

Maka a the subject

a =\frac{b}{7} -5

Swap a and b again

b =\frac{a}{7} -5

Hence:

b(a) =\frac{a}{7} -5

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How much longer is the hypotenuse of the triangle than its shorter leg?
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This is an incomplete question, here is a complete question and image is also attached below.

How much longer is the hypotenuse of the triangle than its shorter leg?

a. 2 ft

b. 4 ft

c. 8 ft

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Step-by-step explanation:

Using Pythagoras theorem in ΔACB :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(AB)^2=(AC)^2+(BC)^2

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