The answer would be 34/100 or 17/50 if reduced .
Answer: the actual length and width of the room is 24ft by 36ft
Step-by-step explanation:
The scale on the architectural plans for a new house is 1 in. equals 4 ft. This means that every 1 inch on the on the architectural plan represents 4 feet on the actual building.
Therefore, if the length of the room as measured on the drawing is 6 inches, the actual length of the room will be
6 × 4 = 24 feet
Also, if the width of the room as measured on the drawing is 9 inches, the actual width of the room will be
9 × 4 = 36 feet
Answer:
84.05 lbs, I think...
Step-by-step explanation:
I divided 164 by 80 and got 2.05
Then I multiplied 2.04 by 41.......I might be wrong... But hopefully I'm not..
Answer:

Possible values of x: Any from 0 to 5.






Step-by-step explanation:
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this question:

So

Possible values of x: 5 trials, so any value from 0 to 5.
For each value of x calculate p(☓ =x)






