The answer would be E. 2a.
Answer:
6J
Step-by-step explanation:
This is an answer from another person but here...
Answer:
The height is 20
The max profit is 1600
Step-by-step explanation:
P (h) = -4h^2 + 160h
The vertex is at
-b/2a = -160/2(-4) = 160/8 = 20
The height that will give the maximum profit is 20
We want to find the value at 20
P(40) =-4(20)^2 +160(20)
=-1600+3200
1600
1:2 can equal 1/2. Hope this helps >^_^<
Answer:
7.6 seconds
Step-by-step explanation:
To solve this problem we can use the following equation:
S = So + 113*t + at^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
In this problem, we have that S = 0, So = 65, Vo = 113 and a = -32 ft/s2 (The acceleration of gravity)
So we have that:
0 = 65 + 113t - 16t2
16t2 - 113t - 65 = 0
Using Bhaskara's formula, we have:
Delta = 113^2 + 4*65*16 = 16929
sqrt(Delta) = 130.11
t = (113 + 130.11) / (2*16) = 7.597 seconds
Rounding to nearest tenth, we have t = 7.6 seconds
