This is what we know:4x^2 + 12x + c = (2x + k)^2
<span>
4x^2 + 12x + c = 4x^2 + 2kx + 2kx + k^2
c=9
</span>
Answer:
Dd
Step-by-step explanation:
Answer:
--- small circle
--- big circle
Step-by-step explanation:
Given
-- sum of areas

Required
The radius of the larger circle
Area is calculated as;

For the smaller circle, we have:

For the big, we have

The sum of both is:


Substitute: 


Substitute 

Factorize
![80\pi = \pi[ r^2 + 4r^2]](https://tex.z-dn.net/?f=80%5Cpi%20%3D%20%5Cpi%5B%20r%5E2%20%2B%204r%5E2%5D)
![80\pi = \pi[ 5r^2]](https://tex.z-dn.net/?f=80%5Cpi%20%3D%20%5Cpi%5B%205r%5E2%5D)
Divide both sides by 

Divide both sides by 5

Take square roots of both sides


The radius of the larger circle is:


