Answer:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:

Where
represent the number of credits and
the grade for each subject. From this case we can find the following sum:

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

And we can solve for
and solving we got:

And from the previous result we got:

And solving we got:

And then we can find the mean with this formula:

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Answer:
1:50 scale
Step-by-step explanation:
9.5m * 100 = 950cm
950/19 = 50
Assuming he had not dealt with the bank offering plan B before, he has nothing deposited two years back. Hence plan B only gives him only 0.2% annual interest for his deposit.
Plan A gives 0.25% for his deposit all the time.
So plan A is more advantageous.
For durations,
To reach $1,000,000 from $100,000, the money needs to grow 10 fold, or
(1+i)^n=10
n=log(10)/log(1+i).
So for plan A:
n=log(10)/log(1.0025)=922.18 years, while for
plan B
n=log(10)/log(1.0020)=1152.44 years.
Hope the bank(s) still exist at that time.
NOTES:
- squared (²) means multiply that number by itself 2 times
- cubed (³) means multiply that number by itself 3 times
- square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
- cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
Answer: (C) 41
<u>Step-by-step explanation:</u>
![\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41](https://tex.z-dn.net/?f=%5Cquad%206%5E2%2B%5Csqrt%5B3%5D%7B125%7D%20%5C%5C%3D%206%20%5Ccdot%206%2B%5Csqrt%5B3%5D%7B5%5Ccdot%205%20%5Ccdot%205%7D%5C%5C%3D%2036%20%2B%205%5C%5C%3D%2041)
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Answer: (C) 10
<u>Step-by-step explanation:</u>
![\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B27%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B81%7D)
![=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}](https://tex.z-dn.net/?f=%3D%5Cbigg%28%5Cdfrac%7B7%7D%7B3%7D%5Ctimes%20%5Csqrt%5B3%5D%7B3%5Ccdot%203%20%5Ccdot%203%7D-2%5Cbigg%29%5Ctimes%20%5Cdfrac%7B1%7D%7B5%7D%20%2B%20%5Csqrt%7B9%5Ccdot%209%7D)





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8² = 8 · 8 = 64 11² = 11 · 11 = 121
5³ = 5 · 5 · 5 = 125 3³ = 3 · 3 · 3 = 27
![\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%3D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%7D%3D4)
![\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B8000%7D%3D%5Csqrt%5B3%5D%7B20%5Ccdot%2020%5Ccdot%2020%7D%3D20)
Answer:
060.28
Step-by-step explanation:
3 can't go into 1, but it goes into 18 six times with 0 left over. 3 goes into 0 zero times. 3 goes into 5 one time with 2 left over. 3 goes into 26 (because you pull the 6 down) 8 times with 2 left over.