I'm not sure what you want with the first part (3/1=6/2)
well PEMDAS or parenthasees exponents, mult or division whichever comes first, addition subtraction, whichever comes first so
3-1/1 would be divison first
1/1=1
3-1=2
Rewrite the equation as
2lw+2lh+2wh=a.2lw+2lh+2wh=a
Subtract
2lh
from both sides of the equation.
2lw+2wh=a−2lh
Factor
2w out of 2lw+2wh.
2w(|+h)=w−2lh
Divide each term by
2(l+h)
and simplify.
.w=a−2lh2(l+h)
Answer: 0.31
Step-by-step explanation:
Let A denotes the event of Tampa Bay Buccaneers will score a touchdown on their opening drive and B denote the event that their defense will have 3 or more sacks in the game.
Given : P(A)=0.14 P(B) = 0.31 P(A or B)=0.14
Formula : P(A and B)= P(A) + P(B) - P(A or B)
Now, the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game will be :-
P(A and B)= 0.14 + 0.31 - 0.14=0.31
Hence, the required probability : 0.31