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aleksklad [387]
3 years ago
9

Solve this equation x-y=53x+y=3​

Mathematics
1 answer:
Evgen [1.6K]3 years ago
4 0

Answer: look at the picture

Step-by-step explanation: Hope this help :D

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A doctor sees each of her patients for 25 minutes during a typical appointment how many patients can she see in a typical 7 and
suter [353]
18 patients

25 min = 0.4166 hours
7.5 hours / 0.4166 = 18
8 0
3 years ago
Need help plz im big dum dum -_-
melamori03 [73]

Answer:

603

Step-by-step explanation:

First divide to get unit rate:

737/11= 67

Then  multiply:

67*9= 603

Hope this helps! :)

5 0
2 years ago
Read 2 more answers
Joseph needs 345 cement blocks to build a wall 40 cm thick. He needs 205 cement blocks to build a wall 25 cm thick. Each block c
IrinaVladis [17]

9514 1404 393

Answer:

  $105

Step-by-step explanation:

The thicker wall takes 345 -205 = 140 more blocks. Each of those costs $0.75, so the added blocks will cost ...

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The thicker wall will cost $105 more.

7 0
3 years ago
Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple rando
cupoosta [38]

Answer:

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

5 0
3 years ago
1.<br> 3z^2+ 8z-3<br> in quadratic formula
tensa zangetsu [6.8K]

Answer:

What grade of math is this?

Step-by-step explanation:

4 0
3 years ago
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