Answer:
Question 1: 4.5(10^−7)(2(10^4))
=
9/1000
(Decimal: 0.009)
Question 2:
mass of neutron/mass of electron = 2*10-24/(9*10-28)
2x10^(-24)/9x10^(-28)
d is closest.
Question 3:
4(10^3)(12(10^5))
=4000*1200000
=4*1000*12*100000
=(4*12)*(1000*100000)
=48*100000000
=4800000000
And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em><em>if</em><em> </em><em>so</em><em> </em><em>pls</em><em> </em><em>mark</em><em> </em><em>brainliest</em><em> </em><em>and</em><em> </em><em>heart</em><em>/</em><em>rate</em><em>!</em>
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
Answer:

Step-by-step explanation:
Midpoint formula is
---------------(1)
Here

Substituting values in equation (1)


B
First you have to change 2 1/2 into 5/2
To multiply fractions use the method
Keep Change Flip
5/2 x 3/1 =15/2
Which simplifies to 7 1/2