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atroni [7]
3 years ago
6

If beaver family one can cut down and 20" tree in 15 minutes and family two can cut down a tree 3 times the size in twice as lon

g how long will it take the second beaver family to cut down a 20" tree
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

10 minutes

Step-by-step explanation:

Beaver family 2 can cut down 60'' (20 x 3) tree in 30 (15 x 2) minutes

In one minute, beaver family 2 would cut down 60/30 = 2'' tree

time to cut down 20'' tree = 20/2 = 10 minutes

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I need help with a math question
Julli [10]

Answer:

Question 1: 4.5(10^−7)(2(10^4))

=

9/1000

(Decimal: 0.009)

Question 2:

mass of neutron/mass of electron = 2*10-24/(9*10-28)

2x10^(-24)/9x10^(-28)

d is closest.

Question 3:

4(10^3)(12(10^5))

=4000*1200000

=4*1000*12*100000

=(4*12)*(1000*100000)

=48*100000000

=4800000000

And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em><em>if</em><em> </em><em>so</em><em> </em><em>pls</em><em> </em><em>mark</em><em> </em><em>brainliest</em><em> </em><em>and</em><em> </em><em>heart</em><em>/</em><em>rate</em><em>!</em>

3 0
3 years ago
Iq scores are normally distributed with a mean of 100 and a standard deviation of 15 what is the probability that a randomly sel
a_sh-v [17]
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:

z = x - mean/s.d.

where x is our I.Q. we are looking for

So we plug in our numbers and we get:

126-100/15 = 1.73333

Next we look at our z-score table for our P-value and I got 0.9582

Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get

1 - 0.9582 = 0.0418

Since they are asking for the probability, we multiply our P-value by 100, and we get 

0.0418 * 100 = 4.18%

And our answer is

4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
6 0
3 years ago
Determine the midpoint between the two points x(4,-6) and y(-2,8)
ikadub [295]

Answer:

p(a, b) = (1, 1)

Step-by-step explanation:

Midpoint formula is

p(a, b)=(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} ) ---------------(1)

Here

(x_1, y_1) = (4, -6) \ \ \ and \ \ \ (x_2, y_2) = (-2, 8)

Substituting values in equation (1)

p(a, b)=(\frac{4 - 2}{2}, \frac{-6 + 8}{2} )

p(a, b) = (1, 1)

6 0
3 years ago
Find the mean, variance &amp;a standard deviation of the binomial distribution with the given values of n and p.
MrMuchimi
A random variable following a binomial distribution over n trials with success probability p has PMF

f_X(x)=\dbinom nxp^x(1-p)^{n-x}

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1

The mean is given by the expected value of the distribution,

\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}
\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}
\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}

The remaining sum has a summand which is the PMF of yet another binomial distribution with n-1 trials and the same success probability, so the sum is 1 and you're left with

\mathbb E(x)=np=126\times0.27=34.02

You can similarly derive the variance by computing \mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2, but I'll leave that as an exercise for you. You would find that \mathbb V(X)=np(1-p), so the variance here would be

\mathbb V(X)=125\times0.27\times0.73=24.8346

The standard deviation is just the square root of the variance, which is

\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834
7 0
3 years ago
PLEASE HELP!!!!!!
quester [9]

B

First you have to change 2 1/2 into 5/2

To multiply fractions use the method
Keep Change Flip

5/2 x 3/1 =15/2

Which simplifies to 7 1/2
6 0
3 years ago
Read 2 more answers
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