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never [62]
3 years ago
7

It takes more time to heat 100 liters of water than 10 liters of water because _____.

Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0

Answer:

boiling point decreases with a decrease in volume. there are more molecules to heat in 100 liters than in 10 liters. the molecules are closer together in 100 liters than in 10 liters

Step-by-step explanation:

mixas84 [53]3 years ago
3 0
<span>... because there are more molecules to heat in 100 liters than in 10 liters.

_____
This assumes energy is supplied to the water at a constant rate, and that the various volumes of water are liquid at the same starting temperature and pressure.</span>
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Answer:
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step-by-step explanation:
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3 years ago
12,11,28,27,44,43,60,59 what number pattern?
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6 0
3 years ago
Read 2 more answers
You have $85 in your bank account. Each week you plan to deposit $9 from your allowance and $20 from your paycheck. The equation
marta [7]

Answer:

85+29x = 250

-85            -85

29x = 290

x = 10

10 weeks

Step-by-step explanation:

7 0
3 years ago
Solve these [7x+5](8x+3)<br> (3-8x)(4-5x)<br> 2(4x+7)(6x-5)
masha68 [24]

Answer:

107520x6+89344x5−241808x4−55444x3+121478x2+6030x−12600

Step-by-step explanation:

brailiest

7 0
2 years ago
A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n
mafiozo [28]

Answer:

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

\hat p=\frac{40}{120}=0.333 estimated proportion of strawberries damaged

p_o=0.25 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

6 0
3 years ago
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