Answer:
(2x-3) (2x+3)
zeros, x intercepts: -3/2, 3/2
Step-by-step explanation:
4x^2 -9
We know the difference of squares is a^2 -b^2
This factors into (a-b) (a+b)
Let 4x^2 =a^2
Taking the square root
2x =a
Let b^2 =9
Taking the square root
b= 3
(4x^2-9 ) = (2x-3) (2x+3)
To find the zeros, we set the equation equal to zero
(4x^2-9 ) = (2x-3) (2x+3) =0
Using the zero product property
2x-3 =0 and 2x+3 =0
2x-3+3 = 0+3 2x+3-3 = 0-3
2x=3 2x=-3
Divide by 2
2x/2 = 3/2 2x/2 = -3/2
x = 3/2 x = -3/2
These are the zeros of the equation (which are also the x intercepts)
5,8,11,14,17,20,23,26,29,32,35,38,41
Add each number by 3
13th term is 41 ( first choice)
The product of 4xy and y² + 2x can also be written as
4xy(y² + 2x)
When we have brackets like this, we multiply whatever is left of the brackets by everything inside.
1) 4xy multiplied by y²
4xy x y² = 4xy³
2) 4xy multiplied by 2x
4xy x 2x = 8x²y
3) Add together 4xy³ and 8x²y
4xy³ + 8x²y
125/12 would be your equivalent improper fraction
Answer:
D. 4 hundredths
Step-by-step explanation:
Hello!
The second digit after the decimal point is 4 is shown by
0.04
The points after a decimal point go tenths, hundredths, thousandths etc.
The answer is D. 4 hundredths
Hope this helps!