Answer:
- The equation that represent the cost C of renting a car and driving x miles is C = $39.11 + $0.50x
- $130 can travel 181.32 miles
Step-by-step explanation:
From the question, a rental company rents a luxury car at a daily rate of 39.34 $ plus $.50 per mile, that is
$0.50 is added to the initial $39.34 for every mile.
The equation that represent the cost C of renting a car and driving x miles is
C = $39.34 + $0.50x
Now, to determine how many miles 130$ can travel,
we will put C = $100, and determine x in the above equation
$130 = $39.34 + $0.50x
$130 - $39.34 = $0.50x
$90.66 = $0.50x
x = $90.66/$0.50
x = 181.32
Hence, $130 can travel 181.32 miles
The answer is A!! hope i helped
Answer:
x=y/4
Step-by-step explanation:
Simply divide by 4 to get x by itself
PART A:
The generic equation of the line is:
y-yo = m (x-xo)
First we look for the slope of the line:
m = (y2-y1) / (x2-x1)
m = ((5000) - (6000)) / (4-3)
m = -1000
Then, we substitute any point in the generic equation:
(xo, yo) = (4, 5000)
Substituting:
y-5000 = (- 1000) (x-4)
Rewriting:
y = -1000x + 4000 + 5000
y = -1000x + 9000
The equation is:
y = -1000x + 9000
PART B:
For the price of 3.50 we have:
y = -1000 * (3.5) +9000
y = 5500
5a.
18/9 = 12/x
18x = 12(9)...cross multiply
18x = 108
x=108/18
x=6
