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2 years ago

14

Which equation below would be perpendicular to the line y = 2?

2 answers:

mr_godi [17]2 years ago

5 0

I believe that the answer is Y=1/5x

nadya68 [22]2 years ago

3 0

Answer:
A) y=1/5x
Step-by-step explanation:
Coz, the way you identify a perpendicular line is by looking for its negative reciprocal. The neagtive reciprocal of 5= 1/5
Now, to check the ans we can multiply the negative reciprocal by "m"
(m in y=mx+c or y=mx+b)
in this case the "m" is stated as 5, so all we need to do is 1/5*5 if the ans is 1 then your ans is right....and over here it is
So thats how you identify & check perpendicular lines!

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Simplify (x^2)^3*5x/6x^2*15x^3

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When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2

<h3>Data obtained from the question</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Simplification =?

<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>

[(x^2)^3 × 5x] / [6x^2 × 15x^3]

Recall

(M^a)^b = M^ab

Thus,

(x^2)^3 = x^6

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]

Recall

M^a × M^b = M^(a+b)

Thus,

x^6 × 5x = 5x^(6 + 1) = 5x^7

6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5

[x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5

Recall

M^a ÷ M^b = M^(a - b)

Thus,

5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2

Therefore,

[(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2

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