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3 years ago

Rewrite each sum as a product of a gcf as a new sum 9+15

Mathematics

2 answers:

Crazy boy [7]3 years ago

7 0

4 +5 = 9 and 12 + 3 =15 and there is more than this
hope I helped

mario62 [17]3 years ago

4 0

4 +5 = 9 and 12 + 3 =15 4 +5 = 9 and 12 + 3 =15

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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Step-by-step explanation:

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Drag steps of the solution into order to solve for x in the equation 9(x + 3) = 108.

Marat540 [252]

Answer:

Given expression is,

9(x+3) = 108

In solving the equation the steps are as follows,

Step 1 : 9x + 27 = 108 ( By distributive property )

Step 2 : 9x = 81 ( Subtracting 108 on both sides )

Step 3 : x = 9 ( Divide both sides by 9)

Hence, by the above explanation we can drag the steps of solution in correct order.

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