Vertex Form of Quadratic Equation - MathBitsNotebook(A1 - CCSS Math) f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola. FYI: Different textbooks have different interpretations of the reference "standard form" of a quadratic function...:)
Had to do a bit of guesswork to figure out what you're asking here. If you're given the 2 angles pi/4 and pi/6, you can find any trig function of either angle.
The sine of pi/4 is 1 / sqrt(2); the cosine is the same.
The cosine of pi/6 is sqrt(3) / 2; the sine of pi/6 is 1/2.
If this isn't quite what you were looking for, try paraphrasing your question to make it clearer.
Domain: x is greater than or equal to 7
Range: y is greater than or equal to 9
The answer would be B. All you would do is subtract 6.4 - 2.06 and you would annex a zero after the four. Then you would get 4.34
Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB
Ans: 4