sin2x =12/13
cos2x = 5/13
tan2x = 12/5
STEP - BY - STEP EXPLANATION
What to find?
• sin2x
,
• cos2x
,
• tan2x
Given:
tanx = 2/3 = opposite / adjacent
We need to first make a sketch of the given problem.
Let h be the hypotenuse.
We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.
Using the Pythagoras theorem;
hypotenuse² = opposite² + adjacent²
h² = 2² + 3²
h² = 4 + 9
h² =13
Take the square root of both-side of the equation.
h =√13
This implies that hypotenuse = √13
We can now proceed to find the values of ainx and cosx.
Using the trigonometric ratio;
![\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}](https://tex.z-dn.net/?f=%5Csin%20x%3D%5Cfrac%7Bopposite%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B2%7D%7B%5Csqrt%5B%5D%7B13%7D%7D)
![\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}](https://tex.z-dn.net/?f=%5Ccos%20x%3D%5Cfrac%7Badjacent%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B3%7D%7B%5Csqrt%5B%5D%7B13%7D%7D)
And we know that tanx =2/3
From the trigonometric identity;
sin 2x = 2sinxcosx
Substitute the value of sinx , cosx and then simplify.
![\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})](https://tex.z-dn.net/?f=%5Csin%202x%3D2%28%5Cfrac%7B2%7D%7B%5Csqrt%5B%5D%7B13%7D%7D%29%28%5Cfrac%7B3%7D%7B%5Csqrt%5B%5D%7B13%7D%7D%29)
Hence, sin2x = 12/13
cos2x = cos²x - sin²x
Substitute the value of cosx, sinx and simplify.
![\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\ \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ccos%202x%3D%28%5Cfrac%7B3%7D%7B%5Csqrt%5B%5D%7B13%7D%7D%29%5E2-%28%5Cfrac%7B2%7D%7B%5Csqrt%5B%5D%7B13%7D%7D%29%5E2%20%5C%5C%20%20%5C%5C%20%3D%5Cfrac%7B9%7D%7B13%7D-%5Cfrac%7B4%7D%7B13%7D%20%5C%5C%20%3D%5Cfrac%7B5%7D%7B13%7D%20%5Cend%7Bgathered%7D)
Hence, cos2x = 5/13
tan2x = 2tanx / 1- tan²x
OR
Hence, tan2x = 12/5
Therefore,
sin2x =12/13
cos2x = 5/13
tan2x = 12/5
Your answer is, get the variable by itself.
The goal in solving an equation is to get the variable by itself on one side of the equation and a number on the other side of the equation. To isolate the variable, we must reverse the operations acting on the variable. We do this by performing the inverse of each operation on both sides of the equation.
<h3><u>
What is an equation?</u></h3>
In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =
<h3><u>
3 types of equations</u></h3>
Thus, <u>option a</u> is your answer.
Learn more about equations here
https://brainly.in/question/5052814
Segment A is a linear constant. In general a linear constant will be y=k for a horizontal line or x=k for a vertical line.
The displacement vector is a vector which gives the point's current position with reference to other points apart from points from the origin. The given length here of the minute hand is the radius and the distance can be written as,
r∠θ
which means that the position can be described by the θ.
The answer choice which is the characteristic of dilations comparing both segments is; A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image
<h3>Which answer choice compares segment E'F' to segment EF?</h3>
By consider the coordinates of the quadrilaterals EFGH and E'F'G'H' as given in the task content image, it follows that the coordinates are as follows;
- E(0, 1), F(1, 1), G(2, 0), and H(0, 0)
- E'(-1, 2), F'(1, 2), G'(3, 0), and H'(-1, 0)
Upon computation of the length of the segments, it follows that the two segments are in proportions. Hence, the answer choice which is correct is; A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image.
Remark:
- A segment that passes through the center of dilation in the pre-image continues to pass through the center of dilation in the image.
- A segment in the image has the same length as its corresponding segment in the pre-image.
- A segment that passes through the center of dilation in the pre-image does not pass through the center of dilation in the image.
- A segment in the image is proportionally longer or shorter than its corresponding segment in the pre-image.
Read more on length of segments;
brainly.com/question/24778489
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