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3 years ago

-5(k + 6) + 7(k – 4)

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

Answer:

2k-58

Step-by-step explanation:

-5(k+6) + 7(k-4)

-5k-30+7k-28

2k-48

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How to translate equation into a sentence j 16=35

timama [110]

J time sixteen equals thirty five.

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4 years ago

Question 2

Free_Kalibri [48]

I’m terms of 12 in is the correct answer.

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2 years ago

Let f ( ) sin(arctan ) x x = . What is the range of f ?

nikklg [1K]

So you have composed two functions,
h(x)=sin(x) and g(x)=arctan(x)
→f=h∘g
meaning
f(x)=h(g(x))
g:R→[−1;1]
h:R→[−π2;π2]
And since
[−1;1]∈R→f is defined ∀x∈R

And since arctan(x) is strictly increasing and continuous in [-1;1] ,
h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]
Meaning
f:R→[arctan(−1);arctan(1)]=[−π4;π4]
so there's your domain

5 0

3 years ago

Upon descent, an airplane is 20,000 feet above the ground. The air traffic control tower is 200 feet tall. It is determined that

PIT_PIT [208]

Answer:

Base length of plane from control tower = 73,880 feet (Approx.)

Step-by-step explanation:

Given:

Height of plane from ground = 20,000 feet

Height of control tower = 200 feet

Angle of elevation from control tower = 15°

Find:

Base length of plane from control tower

Computation:

Height of plane from control tower = 20,000 - 200

Height of plane from control tower = 19,800 feet

Tan θ = Perpendicular / Base

Tan15 = 19,800 / Base length of plane from control tower

0.268 = 19,800 / Base length of plane from control tower

Base length of plane from control tower = 73,880 feet (Approx.)

6 0

3 years ago

Suppose that you are a member of this arbitration panel. Construct a 95% confidence interval for the true mean return of the inv

lisabon 2012 [21]

Answer: Margin of Error = 1.944

Lower Bound = 3.052

Explanation:-

Attached below is a file for monthly Rate of return. Used an excel sheet to determine the confidence interval which seems relatively easier as compared to manual computation. The range below (A2:A40) shows the monthly

Functions used : Standard Deviation as= STDEV (A2:A40)

Sample Mean = AVERAGE(A2:A40)

Margin of Error = CONFIDENCE.T(D4,D5,D2)

Lower Bound Interval = D6-D7 = -3.052

3 0

4 years ago