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VashaNatasha [74]
2 years ago
15

-5(k + 6) + 7(k – 4)

Mathematics
1 answer:
sergiy2304 [10]2 years ago
5 0

Answer:

2k-58

Step-by-step explanation:

-5(k+6) + 7(k-4)

-5k-30+7k-28

2k-48

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Choose the correct simplification of the expression (-9a^3b^2c^10)^0
Flauer [41]

Option C: 1 is the simplification of the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0}

Explanation:

The given expression is \left(-9 a^{3} b^{2} c^{10}\right)^{0}

We need to simplify the given expression.

<u>Simplification:</u>

To simplify the given expression, let us apply the exponent rule, a^{0}=1 where a \neq 0

Thus, the the exponent rule a^{0}=1 means that any value (except zero) to the power of zero is equal to one.

Thus, the expression \left(-9 a^{3} b^{2} c^{10}\right)^{0} becomes,

\left(-9 a^{3} b^{2} c^{10}\right)^{0}=1

Therefore, the simplified expression is 1

Hence, Option C is the correct answer.

8 0
3 years ago
The least common multiple of 3,4,6,8 is
kati45 [8]
The least common multiple is 2
5 0
3 years ago
Read 2 more answers
How<br>Solve The D. E<br><br> dy/dx=2x^5 y^3 - 4y/x<br><br>​
Pachacha [2.7K]
Dy/dx (2x⁵ y³ - 4y/x)

dy/dx (2y³ x⁵ - 4y/x)

dy/dx ( 2y³ x⁵ ) - dy/dx (4y/x)

= 2y³ 5x⁴ - (-4y × 1/x²)

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3 0
2 years ago
What is the radius of this circle if the circumference is 183 cm?
BigorU [14]
I tried to do it and didn’t get any answer choice you provided, but to find the radius of a circle using circumference you take the circumference and divide it by 2 times pie. Which would be 185 or 183/6.28

Hoped this helped you sorry
7 0
3 years ago
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Determine if the matrix below is invertible. Use as few calculations as possible. Justify your answer. [Start 4 By 4 Matrix 1st
Len [333]

Answer:

Yes, it is invertible

Step-by-step explanation:

We need to find in the matrix determinant is different from zero, since iif it is, that the matrix is invertible.

Let's use co-factor expansion to find the determinant of this 4x4 matrix, using the column that has more zeroes in it as the co-factor, so we reduce the number of determinant calculations for the obtained sub-matrices.We pick the first column for that since it has three zeros!

Then the determinant of this matrix becomes:

4\,*Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] +0+0+0

And the determinant of these 3x3 matrix is very simple because most of the cross multiplications render zero:

Det\left[\begin{array}{ccc}1&4&6\\0&3&8\\0&0&1\end{array}\right] =1 \,(3\,*\,1-0)+4\,(0-0)+6\,(0-0)=3

Therefore, the Det of the initial matrix is : 4 * 3 = 12

and then the matrix is invertible

4 0
2 years ago
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