Question

Find the circumcenter of a triangle ABC with vertices at A(2, 2), B(0, -4), and C(7, -1). What is the circumcenter? 20 POINTS ILL MARK BRAINLIEST

Answer 1

just add up the lengths of the three sides

length of AB =

$\sqrt{ {2}^{2} + {6}^{2} }$

length of BC

$\sqrt{ {7}^{2} + {3}^{2} }$

length of CA

$\sqrt{ {5 }^{2} + {1}^{2} }$

(yeah, it's with pythagoras)

let's sum everything up

length AB+BC+CA = 21.011

the units would just be considered as "length units" I guess

hope it helps. have a nice day.

feel free to ask questions.

and maybe, if I'm feeling really nice and a lil bored, i leave greeting answers under yours to enable posters to give gives brainliests. if theres no 2and answer at least