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ANEK [815]
3 years ago
14

Seventy-five beans were equally divided into five pots. How many beans were in each pot?

Mathematics
2 answers:
Ludmilka [50]3 years ago
5 0

Answer:

15

Step-by-step explanation:

if 75 beans is equally divided into 5 pots, divide 75 by 5.

Rasek [7]3 years ago
4 0

Hey!

-----------------------------------

Solution:

75 beans ÷ 5 pots = 15

-----------------------------------

Answer:

15 beans are in each pot!

-----------------------------------

Hope This Helped! Good Luck!

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What is 175% of 8000? Round to the nearest hundredth (if necessary).
igomit [66]

Answer: 175% of 8000 is equal to 14000.

Step-by-step explanation:

We know that to convert a percentage into fraction or decimal , we divide it by 100 .

Also, if find <em>x% of y</em> , then on next step we change '%' sign by \dfrac{1}{100} and  'of ' by Multiply sign (x).

Given problem : 175% of 8000

which can be re-written as: \dfrac{175}{100}\times8000

=\dfrac{175\times80}{1}\\\\=14000 (On solving)

i.e. on solving 175% of 8000, we get 14000

Therefore, 175% of 8000 is equal to 14000.

7 0
3 years ago
Draw the graph of the line that is parallel to y−3=1/3(x+2) and goes through the point (1,7).
horrorfan [7]

Answer:

Step-by-step explanation:

First find the slope of the given line.

y - 3 = 1/3(x+2)

y - 3 = (1/3)x + 2/3

y = (1/3)x + 2/3 + 3

y = (1/3)x + 11/3

Compare it with

y = mx + c

We get m = 1/3

As the parallel lines have same slope, the slope of the second line will also be m= 1/3

y = mx + c

y = (1/3)x + c

As this line goes through the point (1,7), substitute it in the equation:

7 = (1/3)1 + c

7 = 1/3 + c

c = 7 - 1/3

c = 21-1/3

c = 20/3

The equation of the line is found by substituting m = 1/3 and c = 20/3 into the general equation

y = mx + c

y = (1/3)x + 20/3

Graph of the equation is shown

5 0
3 years ago
What is the area of a cross section that is parallel to face ABCD ?
Hunter-Best [27]
To solve this problem you must apply the proccedure shown below:
 1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
 A=12 cm x 6 cm
 2. Therefore, the result is:
 A=72 cm</span>²
 The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
3 0
3 years ago
What is the length of the leg on a right triangle with the other leg measuring 15 inches and the hypotenuse measuring 18 inches
Olegator [25]

\huge \cal \blue{ANSWER}

In this triangle by applying Pythagoras theorem.

H²=B²+P²

18²=15²+P²

324=225+p²

324-225=P²

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9.94

3 0
3 years ago
~PLEASE HELP ASAP OFFERING 30 POINTS~
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The first one is B) september 10 but idk the second one

8 0
3 years ago
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