Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.
Answer:
#1
25
#2
1
#3
5
Step-by-step explanation:
Answer: 1/4
Step-by-step explanation:
To determine the probability of landing on blue, you divide by the total number of spins.
In this experiment, the probability of the spinner landing on blue after 20 spins would be 15%.
This makes the probability of landing on blue to be:
Pr (landing on blue) / Pr (total trials) = 5/20
This gives 1/4
Answer:
(x − 2)(x − 3)
Step-by-step explanation:
x² - 5x + 6
(x − 2)(x − 3)
I’m pretty sure you can make four if you’re distributing them evenly because they can both be decided by four so each kit would get 5 water bottles and 3 cans. I’m not 100% sure but lmk if it helped :)
