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aliina [53]
3 years ago
5

For quadrilateral ABCD, determine the most precise name for it. A(-2,3), B(9,3), C(5,6) and D(2,6). Show your work and explain.

Mathematics
1 answer:
horsena [70]3 years ago
8 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following points given in the problem above:

 A<span>(-2,3), B(9,3), C(5,6) and D(2,6)

 2. When you plot them, you obtain the figure shown in the graph attached. 

 3. Therefore, as you can see, the answer is:  the figure is a trapezoid, which is define as a quadrilateral with two parallel sides.</span>

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A triangle has sides with lengths of 11 miles, 15 miles, and 17 miles. Is it a right triangle?​
dybincka [34]

Answer:

Below.

Step-by-step explanation:

If its a right triangle it will obey the Pythagoras theorem.

17^2 = 289

11^2 + 15^2 = 121 + 225  = 346

- so NOT a right triangle.

3 0
3 years ago
PLEASE HELP FOR BRAINLIEST
tatiyna

Answer:

  • It is a linear equation
  • The graph of the equation will show that the <em>y</em> values increase as the <em>x</em> values increase.

Step-by-step explanation:

The pay Michael gets (y) is the amount per paper ($0.40) multiplied by the number of papers (x) and that product added to the daily base pay of $5. Michael's daily pay (in dollars) can be described by ...

  y = 5.00 + 0.40x

This is a linear equation with a positive slope (meaning y goes up when x goes up).

6 0
3 years ago
Find the vertex.<br> f(x)<br> =<br> 2(x + 7)2 + 8<br> ([?],[ ]
Nana76 [90]
(-7,8)

Simplifying 2(x+7)^2+8
Will give you the image results

You must graph the formula and you’ll get -7,8 (using desmos helps)

6 0
2 years ago
(4) A spherical balloon is being inflated so that its diameter is increasing at a constant rate of 6 cm/min. How quickly is the
fredd [130]

In terms of its radius r, the volume of the balloon is

V(r)=\dfrac{4\pi}3r^3

The diameter d is twice the radius, so that in terms of its diameters, the balloon's volume is given by

V(d)=\dfrac{4\pi}3\left(\dfrac d2\right)^3=\dfrac\pi6d^3

Differentiate both sides with respect to time t:

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2d^2\dfrac{\mathrm dd}{\mathrm dt}

The diameter increases at a rate of \frac{\mathrm dd}{\mathrm dt}=6\frac{\rm cm}{\rm min}. When the diameter is d=50\,\mathrm{cm}, we have

\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi2(50\,\mathrm{cm})^2\left(6\frac{\rm cm}{\rm min}\right)=7500\pi\dfrac{\mathrm{cm}^3}{\rm min}

or about 23,562 cc/min (where cc = cubic centimeters)

5 0
3 years ago
Can you please help me find the value of x and y while l is parallel to m.
12345 [234]

<u>Answer-</u>

<em>The values of x and y are </em><em>13</em><em> and </em><em>24</em><em>, respectively.</em>

<u>Solution-</u>

From the attachment, l and m are parallel lines and

\Rightarrow (5x-8)+(4y+27)=180

\Rightarrow 5x+4y=161    ---------------------1

As, when a traversal line intersects two parallel lines, same-side interior angles are supplementary, or they add up to 180 degrees.

\Rightarrow (7x-31)+63=4y+27

\Rightarrow 7x-4y=-5     ---------------------2

As, an exterior angle is equal to the sum of the opposite interior angles.

Adding equation 1 and 2, we get,

\Rightarrow 5x+4y+7x-4y=161-5  

\Rightarrow 12x=156  

\Rightarrow x=13  

Putting the value of x in equation 1, we get

\Rightarrow y=24

7 0
3 years ago
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