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3 years ago

Write an inequality for the given statement: The sum of x and 25 is less than 75.

1 answer:

4 0

That statement would be best express by " x + 25 < 75 ". Since the statement says the sum of x and 25, thus, it will be x + 25. Then it also states that the sum is less than 75, so the best expression would be " < 75".

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15 increased by a number x

aleksandrvk [35]

15 increased by a number x: 15 + x
a number x more than −14: x > -14
t<span>he difference of 7 and a number x: </span>7/x

3 0

3 years ago

Helppppppppp pleaseeee Someoneeeee pleaseeee I neeed

Stella [2.4K]

Answer:

The minimum value of f(x) is 2

Step-by-step explanation:

To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it

Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)

∵ f(x) = 2x² - 4x + 4

→ Find f'(x)

∵ f'(x) = 2(2) $x^{2-1}$ - 4(1) $x^{1-1}$ + 0

∴ f'(x) = 4x - 4

→ Equate f'(x) by 0

∵ f'(x) = 0

∴ 4x - 4 = 0

→ Add 4 to both sides

∵ 4x - 4 + 4 = 0 + 4

∴ 4x = 4

→ Divide both sides by 4

∴ x = 1

→ The minimum value is f(1)

∵ f(1) = 2(1)² - 4(1) + 4

∴ f(1) = 2 - 4 + 4

∴ f(1) = 2

∴ The minimum value of f(x) is 2

7 0

2 years ago

Dante sold 413 cups of lemonade last weekend. George sold 297 cups of lemonade last weekend. How many more cups of lemonade did

TEA [102]

Answer:dante sold 116 more cups.

Step-by-step explanation: subtract 297 from 413

6 0

3 years ago

What is 2x12=24 I got the answer

strojnjashka [21]

You were right 24 is the answer. :)

8 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: