= 3(4a^2 + 4a - 3) - 4a^2 + 28
= 12a^2 + 12a - 9 - 4a^2 + 28
= 8a^2 + 12a + 19
= 4a(2a + 3) + 19
The axis of symmetry would be -3 because it is always the (x) of the vertex
Answer:
If PQRS is a parallelogram with two adjacent congruent sides, then it must be a rhombus. A rhombus is a parallelogram characterized by having all sides congruent. Therefore, the adjacent sides must be congruent as well.
Answer:
The answer to your question is: ∠K = 138°
Step-by-step explanation:
m∠N = 42°
m∠K = ?
The sum of all the internal angles in a quadrangle equals 360°
then
∠N + ∠L + ∠M + ∠K = 360°
∠N = ∠ L and ∠M = ∠K
So, 2 ∠N + 2 ∠K = 360
Substitution
2 (42) + 2 ∠K = 360
84 + 2 ∠K = 360
2 ∠K = 360 - 84
2 ∠K = 276
∠K = 276 / 2
∠K = 138°
