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3 years ago

9

20 is 60% of what number

2 answers:

Bumek [7]3 years ago

6 0

Answer:

$\huge{ \boxed{ \tt{33.33}}}$

Step-by-step explanation:

$\star{ \: \sf{ \: Suppose, \: the \: number \: be \: x}}$

$\star \: \sf \: Create \: an \: equation \: and \: solve \: for \: x$

$\underline{ \underline{ \mathfrak{lets \: solve}}} :$

$\sf{ \: 60\% \: \: of \: \: x \: = 20}$

$\text{Step \: 1} : \sf{ \: Convert \: percentage \: ( \%) \: into \: fraction}$

$\sf{To \: do \: so, \: Divide \: it \: by \: 100 \: and \: remove \: the \: \% \: symbol. \: }$

$\sf{Then, \: Simplify \: the \: fraction \: to \: its \: lowest \: term.}$

$\hookrightarrow{ \sf{ \frac{60}{100} x = 20}}$

$\hookrightarrow{ \sf{ \frac{ \cancel{60} ^{ \: \: 3} }{ \cancel{100} \: ^{ \: 5} } x = 20}}$

$\hookrightarrow{ \sf{ \frac{3}{5}x = 20}}$

$\hookrightarrow{ \sf{0.6x = 20}}$

$\text{Step \: 2} : \sf{Divide \: both \: sides \: by \: 0.6}$

$\hookrightarrow{ \sf{ \frac{0.6x}{0.6} = \frac{20}{0.6}}}$

$\text{Step \: 3} : \sf{Calculate}$

$\hookrightarrow{ \sf{x = 33.33}}$

The required number is 33.33

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

Lilit [14]3 years ago

3 0

Answer:

33.33

Step-by-step explanation:

60% of 33.33 is 20. 100% of 33.33 is 33.33, therefore 60 percent of 33.33 equals 20.

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Ten subtracted from the quotient of a number and 7 is less than -6

Tresset [83]

Answer: (x ÷ 7) - 10 < -6

Step-by-step explanation:

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2 years ago

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t

andrezito [222]

Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ. $e^{-\lambda.x}$

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - $e^{-\lambda.x}$

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - $e^{-0.0143.100}$

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - $e^{-0.0143.200}$

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = $\frac{1}{\lambda}$

E(X) = $\frac{1}{0.0143}$

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = $\sqrt{\frac{1}{\lambda^{2}} }$

σ = $\sqrt{\frac{1}{0.0143^{2}} }$

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - $e^{-0.0143*209.79}$ )

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

$\int\limits^m_0 f({x}) \, dx$ = 0.5

$\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx$ = 0.5

$\lambda.\frac{e^{-\lambda.x}}{-\lambda}$ = $-e^{-\lambda.x} + e^{0}$

$1 - e^{-\lambda.m}$ = 0.5

$-e^{-\lambda.m}$ = - 0.5

ln( $e^{-0.0143.m}$ ) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

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2 years ago

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3 years ago

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Answer:

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