2 lawns per hour is the answer
A population of deer had 200 individuals and 15% were lost in one year. We can calculate the number of deer that were lost with proportion:
200 deer ------------------------100%
x deer ------------------------ 15%
-----------------------------------------------
200 : x = 100 : 15
200 * 15 = 100 x
3,000 = 100 x
x = 3,000 : 100
x = 30
Answer: 30 deer were lost in one year.
Simple interest: i = p * r * t; compound interest would be A=p(1+r/n)^(nt)
Here, A = $500 (1.10)^2 = $605 (answer for "once per year."
Once per month:
A = $500 (1 + 0.10/12)^(12*2) = $610.20
Once per week: Can y ou figure that out? # of compounding periods is 12 per year in this problem.
First of we know that B and C is definitely wrong.
then D is unrealistic so A is the correct answer.
It is a really simple question.
Answer:
(a) z(105)= (105-95)/10
= 1
z(85)= (85-95)/10
= -1
P(85< x < 105) = P(-1< z < 1) = 0.6825
Quantity of people of 1600 that have IQ between 85 and 115 = 0.6825*1600= 1092
(b) z(105) = (115-95)/10 = 2
z(85) = (75-95)/10 = -2
P(-2< z < 2) = 0.6827
quantity of people of 1600 that have IQ between 75 and 115 = 0.6825x1600=1092
(c) Z(>125)=( 125-100)/10=3