Answer: ok i don't know but you can copy and paste the question then search it in the search bar because i can guaranty that someone has asked that question before. and then all you got to do that and you can keep your points. hope this helps! ;)
Step-by-step explanation:
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
3x+x+20 = 180
4x = 180-20
4x = 160
x = 40
×+20+3x+2x+38+C=360
40+20+3×40+2×40+38+C=360
40+20+120+80+38+C=360
298+C=360
C=360-298
C =62°
A is the correct awnser good luck
