Base from the given system of equation, there would be only one possible solution. This is the point where the lines meet or intersect with each other. Hope this answers the question. Have a nice day. Feel free to ask more question.
Answer:
Yes
The common difference is .6
Step-by-step explanation:
Take the second term and subtract the first term
-2.2 - (-2.8)
-2.2+ 2.8 = .6
Take the third term and subtract the second
-1.6 - (-2.2)
1.6 +2.2
The common difference is .6
Answer:
Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.
Step-by-step explanation:
The data given is
Population mean μ= $ 7.18
Population variance= σ²= 3.81
Population Standard Deviation = √σ²= √3.81= 1.952
Sample Mean= x`= $ 8.02
Sample Standard Deviation =s = $ 2.08
Sample Size = 15
Significance Level = ∝= 0.05
The null and alternate hypotheses are
H0: σ1=σ2 against the claim that Ha: σ1≠ σ2
where σ1 is the population variance and
σ2 is the sample variance
The rejection region is Z ≥ ±1.96 for two tailed test at ∝= 0.05
The test statistic z is used
z= x`- μ/ σ/√n
Putting the values
Z= 8.02-7.18/1.952/√15
z= 0.84/0.51599
z= 1.6279
Since the calculated value of z= 1.6279 does not fall in the critical region Z ≥ ±1.96 we conclude that there is no difference between the population variance and the sample variance.
Hypothesis (p): A polygon is a square
Conclusion: (q): It is a rectangle
Inverse: q → p <em>If a polygon is a rectangle, then it is a square</em>
Converse: ~p → ~q <em>If a polygon is not a square, then it is not a rectangle.</em>
Contrapositive: ~q → ~p <em>If a polygon is not a rectangle, then it is not a square</em>
Your answers are correct
It’s the letter “B” I think
