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3 years ago

I need help on this equation

Mathematics

2 answers:

pychu [463]3 years ago

8 0

T = 4d + 2

because 4 tables each day (d), and add on the 2 that he made at the start

Firdavs [7]3 years ago

7 0

Answer choice F is correct . He builds 4 tables each day so that’s your rate of change 4d because d equal each day and starts of with 2 so +2

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zhannawk [14.2K]

Answer:

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Step-by-step explanation:

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2 years ago

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tester [92]

Answer:

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Step-by-step explanation:

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2 years ago

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Pachacha [2.7K]

The capital formation of the investment function over a given period is the

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(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

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(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

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$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

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