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3 years ago

Find the most general antiderivative of the function. (Use C for the constant of the antiderivative).

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

$x^6 - \frac{7x^5}{5} - 3x^3 + C$

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Pleaseee help on this❤️

Dominik [7]

B is incorrect which means it is the answer

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2 years ago

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Find the area of this shape<br> giving brainliest please help

pogonyaev

ANSWER: ⇒ 366.19cm²

I hope this helps you :)

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2 years ago

Connor rolled a die 6 times. A 2 occurred three times. Why isn't the theoretical probability 3/6 instead of 1/6?

Cerrena [4.2K]

2 occurred 3times

$\\ \sf\longmapsto S=6\times 3=18$

$\\ \sf\longmapsto |S|=18$

Now

$\\ \sf\longmapsto E=No\:of\:times\: 2\:occured$

$\\ \sf\longmapsto |E|=3$

we know

$\boxed{\sf P(E)=\dfrac{|E|}{|S|}}$

$\\ \sf\longmapsto P(E)=\dfrac{3}{18}$

$\\ \sf\longmapsto P(E)=\dfrac{1}{6}$

6 0

3 years ago

Divide 2,756 into 1,375,244

alexgriva [62]

Answer:

499

Step-by-step explanation:

you take 1,375,244/2,756=499

3 0

3 years ago

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Trapezia ABCD and PQRS are similar.<br> Find the area shaded in green.

avanturin [10]

The area shaded in green is 864 cm²

<h3>Similar figures</h3>

Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,

AB / PQ = CD / RS

30 / 10 = 24 / RS

30RS = 240

RS = 240 / 30

RS = 8 cm

let find the height of trapezium PQRS.

AB / PQ = 36 / h

30 / 10 = 36 / h

30h = 360

h = 360 / 30

h = 12 cm

Therefore,

area of the green portion = area of ABCD - area of PQRS

<h3>Area of a trapezium</h3>

area = 1 / 2(a + b)h

Therefore,

area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²

area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²

Area of the green portion = 972 - 108 = 864 cm²

learn more on trapezium here: brainly.com/question/11961445

6 0

2 years ago