All categories

3 years ago

Whats 91 divided by 2605

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

6 0

Answer: 0.34339622641509433962264150943396

Step-by-step explanation: I basically just divided, but if you wanted the rounded version, it is 0.34

zhenek [66]3 years ago

6 0

Answer:

91/2605=0.03493282149

2605/91=28.6263736264

DON'T FORGET TO ROUND HOPE THIS HELPS

Step-by-step explanation:

You might be interested in

What point is located on the x-axis<br><br> Pls help

qaws [65]

Answer:

Point C is located on the x-axis.

Step-by-step explanation:

edge 2020

7 0

3 years ago

Read 2 more answers

Given that a function, g, has a domain of -20 sxs 5 and a range of 5 s 39 s 45 and that g(0) = -2 and g(-9) = 6, select the stat

luda_lava [24]

Answer:

option (B) and (D)

Step-by-step explanation:

It's just basic of domain and range just check out the domain and range you can get your answer .

Only option (B) and (D) satisfy in the given range and domain

8 0

3 years ago

Please help I need to turn this in today.

Bogdan [553]

Answer:

Step-by-step explanation:

If you have a Ti-84 series calculator, press "stat" then "Edit..." and then fill in the data table values for x and y in two lists. Then press "2nd" and "mode" to quit. Now press "stat" again and right arrow over to "calc" and press down until you find "ExpReg" and set the "Xlist" and "Ylist" that you used and you will get C as the answer. Another way to do this is to manually substitute values into all 4 equations, which is boring.

8 0

1 year ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

4 0

3 years ago

I suck at math and i really need help asap!

AlladinOne [14]

Answer:

Step-by-step explanation:

2^{4-3}

3 0

3 years ago

Read 2 more answers