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labwork [276]
3 years ago
13

Which system is equivalent to

Mathematics
2 answers:
Kaylis [27]3 years ago
8 0

Answer:

d

Step-by-step explanation:

sammy [17]3 years ago
6 0

<u>Answer:</u>

D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11

<u>Step-by-step explanation:</u>

We are given the following two expressions:

3x^2-4y^2=25

and

-6x^2-2y^2=11

Now if we look at the option D) 6x^2 - 8y^2 = 50&#10; and -6x^2 - 2y^2 = 11, we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25

and the later part -6x^2 - 2y^2 = 11 is already the same.

Therefore, the correct answer option is D)  6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

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Can anyone please help me figure this out ​
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Drag each pair of numbers to show if their greatest common factor (GCF) is less than 2, equal to 2, equal to 3, or greater than
TEA [102]

Answer:

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Step-by-step explanation:

The greatest common Factor (GCF) of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.

(a) 2 and 7: Both 2 and 7 are prime numbers, therefore the GCF of 2 and 7 is 1 which is less than 2.

(b) 2 and 6: Both 2 and 6 are even numbers, therefore the GCF of 2 and 6 is 2.

(c) 4 and 12: Both 4 and 12 are even numbers and multiple of 4, therefore the GCF of 4 and 12 is 4 which is greater than 3.

(d) 12 and 13: 13 is a prime number, therefore the GCF of 12 and 13 is 1 which is less than 2.

(e) 6 and 18: Both 6 and 18 are even numbers and multiple of 6, therefore the GCF of 6 and 18 is 6 which is greater than 2 and greater than 3.

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8 0
3 years ago
42x^2 + 32 - 18 =6062
Elenna [48]
Okay, we start with 42x^2 + 32 - 18 = 6062. To solve single-variable equations like this one, we want to isolate the x by moving all of the other numbers to the other side of the equation. We need to first subtract 32 and 18, and that equals 14. Now our problem looks like this, 42x^2 + 14 = 6062. Since 14 is the only other number on the left side, we subtract four from both sides! This gives us 42x^2 + 14 - 14 = 6062 - 14, so 42x^2 = 6062. Now to find x, we want to just have one x on the left side instead of 42, so we divide the equation by 42 to find that 42x^2/42 = 6048/42, so x = 12
4 0
3 years ago
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